DP Physics (last assessment 2024)

Question 21M.2.HL.TZ1.2b

Date	May 2021	Marks available	[Maximum mark: 1]	Reference code	21M.2.HL.TZ1.2b
Level	HL	Paper	2	Time zone	TZ1
Command term	Calculate	Question number	b	Adapted from	N/A

[Maximum mark: 1]

21M.2.HL.TZ1.2b

A planet is in a circular orbit around a star. The speed of the planet is constant. The following data are given:

Mass of planet    $= 8.0 \times 10^{24}$ kg
Mass of star    $= 3.2 \times 10^{30}$ kg
Distance from the star to the planet R   $= 4.4 \times 10^{10}$ m.

(b)

Calculate the value of the centripetal force.

[1]

Markscheme

$F = \frac{(6.67 \times 10^{- 11}) (8 \times 10^{24}) (3.2 \times 10^{30})}{(4.4 \times 10^{10})^{2}} = 8.8 \times 10^{23}$ «N» ✓

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Core

Core » Topic 6: Circular motion and gravitation » 6.1 – Circular motion

Core » Topic 6: Circular motion and gravitation

Question 21M.2.HL.TZ1.2b

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