DP Physics (last assessment 2024)

Question 22N.2.HL.TZ0.8b.i

Date	November 2022	Marks available	[Maximum mark: 2]	Reference code	22N.2.HL.TZ0.8b.i
Level	HL	Paper	2	Time zone	TZ0
Command term	Show that	Question number	b.i	Adapted from	N/A

b.i.

[Maximum mark: 2]

22N.2.HL.TZ0.8b.i

A satellite is launched from the surface of Earth into a circular orbit.

The following data are given.

Mass of the satellite = 8.0 × 10² kg

Height of the orbit above the surface of Earth = 5.0 × 10⁵ m

Mass of Earth = 6.0 × 10²⁴ kg

Radius of Earth = 6.4 × 10⁶ m

(b.i)

Show that the kinetic energy of the satellite in orbit is about 2 × 10¹⁰ J.

[2]

Markscheme

orbital radius $= 6.4 \times 10^{6} + 5.0 \times 10^{5}$ « $= 6.9 \times 10^{6}$ m» ✓

$KE = \frac{1}{2} \times 8.0 \times 10^{2} \times \frac{6.67 \times 10^{- 11} \times 6.0 \times 10^{24}}{6.9 \times 10^{6}}$ OR $2.3 \times 10^{10}$ «J» ✓

Award [1] max for answers ignoring orbital height (KE = 2.5 × 10¹⁰ J).

Examiners report

This question was well done, with only a few missing the height of the satellite.

Syllabus sections

Additional higher level (AHL)

Additional higher level (AHL) » Topic 10: Fields » 10.2 – Fields at work

Additional higher level (AHL) » Topic 10: Fields

Question 22N.2.HL.TZ0.8b.i

Select a Test

Syllabus sections

Confirm action