DP Physics (last assessment 2024)
Question 23M.2.HL.TZ1.4a
| Date | May 2023 | Marks available | [Maximum mark: 6] | Reference code | 23M.2.HL.TZ1.4a |
| Level | HL | Paper | 2 | Time zone | TZ1 |
| Command term | Calculate, Show that | Question number | a | Adapted from | N/A |
a.
[Maximum mark: 6]
23M.2.HL.TZ1.4a
(a)
A cell of negligible internal resistance and electromotive force (emf) 6.0 V is connected to three resistors R, P and Q.
R is an ohmic resistor. The I-V characteristics of P and Q are shown in the graph.
The current in P is 0.40 A.
(a.i)
Show that the current in Q is 0.45 A.
[3]
Markscheme
Voltage across P is 1.4 «V» ✓
Voltage across Q is 4.6 «V» ✓
And 6 – 1.4 = 4.6 «V» ✓
Need to see a calculation involving the two voltages and the total voltage in the circuit for MP3 (e.g. 1.4 + 4.6 = 6).
(a.ii)
Calculate the resistance of R.
[2]
Markscheme
Current in R is «(0.45 − 0.4)=» 0.05 A ✓
So resistance is « » = 28 «Ω»
Allow ECF from a(i)
Allow ECF from MP1
(a.iii)
Calculate the total power dissipated in the circuit.
[1]
Markscheme
«0.45 × 6.0» = 2.7 «W»✓
