DP Physics (last assessment 2024)
Question 18M.3.SL.TZ1.c.i
Date | May 2018 | Marks available | [Maximum mark: 2] | Reference code | 18M.3.SL.TZ1.c.i |
Level | SL | Paper | 3 | Time zone | TZ1 |
Command term | Explain | Question number | c.i | Adapted from | N/A |
c.i.
[Maximum mark: 2]
18M.3.SL.TZ1.c.i
The pressure–volume (pV) diagram shows a cycle ABCA of a heat engine. The working substance of the engine is 0.221 mol of ideal monatomic gas.
At A the temperature of the gas is 295 K and the pressure of the gas is 1.10 × 105 Pa. The process from A to B is adiabatic.
The process from B to C is replaced by an isothermal process in which the initial state is the same and the final volume is 5.00 × 10–3 m3.
Explain, without any calculation, why the pressure after this change would belower if the process was isothermal.
[2]
Markscheme
for isothermal process, PV = constant / ideal gas laws mentioned
since VC > VB, PC must be smaller than PB
[2 marks]
