DP Physics (last assessment 2024)
Question 18M.3.SL.TZ2.b.i
Date | May 2018 | Marks available | [Maximum mark: 1] | Reference code | 18M.3.SL.TZ2.b.i |
Level | SL | Paper | 3 | Time zone | TZ2 |
Command term | Calculate | Question number | b.i | Adapted from | N/A |
b.i.
[Maximum mark: 1]
18M.3.SL.TZ2.b.i
Observer A detects the creation (event 1) and decay (event 2) of a nuclear particle. After creation, the particle moves at a constant speed relative to A. As measured by A, the distance between the events is 15 m and the time between the events is 9.0 × 10–8 s.
Observer B moves with the particle.
For event 1 and event 2,
calculate the spacetime interval.
[1]
Markscheme
spacetime interval = 272 – 152 = 504 «m2»
[1 mark]
