DP Physics (last assessment 2024)
Question 18M.3.SL.TZ2.a
Date | May 2018 | Marks available | [Maximum mark: 3] | Reference code | 18M.3.SL.TZ2.a |
Level | SL | Paper | 3 | Time zone | TZ2 |
Command term | Suggest | Question number | a | Adapted from | N/A |
a.
[Maximum mark: 3]
18M.3.SL.TZ2.a
An optic fibre of refractive index 1.4475 is surrounded by air. The critical angle for the core – air boundary interface is 44°. Suggest, with a calculation, why the use of cladding with refractive index 1.4444 improves the performance of the optic fibre.
[3]
Markscheme
sin c = or sin c = 0.9978
critical angle = 86.2«°»
with cladding only rays travelling nearly parallel to fibre axis are transmitted
OR
pulse broadening/dispersion will be reduced
OWTTE
[3 marks]
