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Question 18M.2.HL.TZ2.4b.i

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Date May 2018 Marks available [Maximum mark: 2] Reference code 18M.2.HL.TZ2.4b.i
Level HL Paper 2 Time zone TZ2
Command term Show that Question number b.i Adapted from N/A
b.i.
[Maximum mark: 2]
18M.2.HL.TZ2.4b.i

The diagram shows a potential divider circuit used to measure the emf E of a cell X. Both cells have negligible internal resistance.

M18/4/PHYSI/SP2/ENG/TZ2/04

AB is a wire of uniform cross-section and length 1.0 m. The resistance of wire AB is 80 Ω. When the length of AC is 0.35 m the current in cell X is zero.

(b.i)

Show that the resistance of the wire AC is 28 Ω.

[2]

Markscheme

the resistance is proportional to length / see 0.35 AND 1«.00»

so it equals 0.35 × 80

«= 28 Ω»

[2 marks]

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