DP Physics (last assessment 2024)

Test builder »

Question 18N.2.SL.TZ0.a

Select a Test
Date November 2018 Marks available [Maximum mark: 4] Reference code 18N.2.SL.TZ0.a
Level SL Paper 2 Time zone TZ0
Command term Determine Question number a Adapted from N/A
a.
[Maximum mark: 4]
18N.2.SL.TZ0.a

A chicken’s egg of mass 58 g is dropped onto grass from a height of 1.1 m. The egg comes to rest in a time of 55 ms. Assume that air resistance is negligible and that the egg does not bounce or break.

Determine the magnitude of the average decelerating force that the ground exerts on the egg.

[4]

Markscheme

ALTERNATIVE 1:

initial momentum = mv =  2 × 0.058 × 0.63  «= 0.27 kg m s−1»

OR

mv =  0.058 × 2 × 9.81 × 1.1  «= 0.27 kg m s−1» ✔

force = « change in momentum time =»  0.27 0.055  ✔

4.9 «N» ✔

F − mg = 4.9 so F= 5.5 «N» ✔

 

ALTERNATIVE 2:

«Ek = 1 2 mv2 = 0.63 J» v = 4.7 m s−1 ✔

acceleration = « Δ v Δ t =»  4.7 55 × 10 − 3 = «85 m s−2» ✔

4.9 «N» ✔

F − mg = 4.9 so F= 5.5 «N» ✔

Syllabus sections