DP Physics (last assessment 2024)

Question 18N.3.SL.TZ0.5a.ii

Date	November 2018	Marks available	[Maximum mark: 1]	Reference code	18N.3.SL.TZ0.5a.ii
Level	SL	Paper	3	Time zone	TZ0
Command term	Show that	Question number	a.ii	Adapted from	N/A

a.ii.

[Maximum mark: 1]

18N.3.SL.TZ0.5a.ii

The spacetime diagram shows the axes of an inertial reference frame S and the axes of a second inertial reference frame S′ that moves relative to S with speed 0.745c. When clocks in both frames show zero the origins of the two frames coincide.

Event E has coordinates x = 1 m and ct = 0 in frame S. Show that in frame S′ the space coordinate and time coordinate of event E are

(a.ii)

ct′ = –1.1 m.

[1]

Markscheme

t′ = « $\gamma \left( {t - \frac{{vx}}{{{c^2}}}} \right)$ =» $1.499 \times \left( {0 - \frac{{0.745c \times 1}}{{{c^2}}}} \right)$ «= $- \frac{{1.11}}{c}$ »

«ct′ = –1.1 m»

using spacetime interval 0 − 1² = (ct′)² − 1.5² ⇒ «ct′ = –1.1» ✔

Syllabus sections

Option A: Relativity

Option A: Relativity » Option A: Relativity (Core topics) » A.2 – Lorentz transformations

Option A: Relativity » Option A: Relativity (Core topics)

Question 18N.3.SL.TZ0.5a.ii

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