DP Physics (last assessment 2024)

Question 18N.3.SL.TZ0.b.ii

Date	November 2018	Marks available	[Maximum mark: 2]	Reference code	18N.3.SL.TZ0.b.ii
Level	SL	Paper	3	Time zone	TZ0
Command term	Determine	Question number	b.ii	Adapted from	N/A

b.ii.

[Maximum mark: 2]

18N.3.SL.TZ0.b.ii

The diagram shows the longest and shortest paths that a ray can follow inside the fibre.

For the longest path the rays are incident at the core–cladding boundary at an angle just slightly greater than the critical angle. The optic fibre has a length of 12 km.

Determine the time delay between the arrival of signals created by the extra distance in (b)(i).

[2]

Markscheme

speed of light in core is $\frac{{3.0 \times {{10}^8}}}{{1.52}} = 1.97 \times {10^8}$ «m s⁻¹» ✔

time delay is $\frac{{66}}{{1.97 \times {{10}^8}}} = 3.35 \times {10^{ - 7}}$ «s» ✔

Syllabus sections

Option C: Imaging

Option C: Imaging » Option C: Imaging (Core topics) » C.3 – Fibre optics

Option C: Imaging » Option C: Imaging (Core topics)

Question 18N.3.SL.TZ0.b.ii

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