DP Physics (last assessment 2024)

Question 18N.3.HL.TZ0.6a

Date	November 2018	Marks available	[Maximum mark: 1]	Reference code	18N.3.HL.TZ0.6a
Level	HL	Paper	3	Time zone	TZ0
Command term	Show that	Question number	a	Adapted from	N/A

[Maximum mark: 1]

18N.3.HL.TZ0.6a

An electron with total energy 1.50 MeV collides with a positron at rest. As a result two photons are produced. One photon moves in the same direction as the electron and the other in the opposite direction.

(a)

Show that the momentum of the electron is 1.41 MeV c^–1.

[1]

Markscheme

$pc = \sqrt {{E^2} - {{\left( {m{c^2}} \right)}^2}} = \sqrt {{{150}^2} - {{0.511}^2}}$ «= 1.410 MeV» ✔

Syllabus sections

Option A: Relativity

Option A: Relativity » Option A: Relativity (Additional higher level option topics) » A.4 – Relativistic mechanics (HL only)

Option A: Relativity » Option A: Relativity (Additional higher level option topics)

Question 18N.3.HL.TZ0.6a

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