DP Chemistry (first assessment 2025)
Question 22M.2.SL.TZ2.8f(i)
Date | May 2022 | Marks available | [Maximum mark: 3] | Reference code | 22M.2.SL.TZ2.8f(i) |
Level | SL | Paper | 2 | Time zone | TZ2 |
Command term | Calculate | Question number | f(i) | Adapted from | N/A |
f(i).
[Maximum mark: 3]
22M.2.SL.TZ2.8f(i)
(f(i))
Calculate the enthalpy change of the reaction, ΔH, using section 11 of the data booklet.
[3]
Markscheme
bond breaking: C–H + Cl–Cl / 414 «kJ mol–1» + 242 «kJ mol–1»/656 «kJ»
OR
bond breaking: 4C–H + Cl–Cl / 4 × 414 «kJ mol–1» + 242 «kJ mol–1» / 1898 «kJ» ✔
bond forming: «C–Cl + H–Cl / 324 kJ mol–1 + 431 kJ mol–1» / 755 «kJ»
OR
bond forming: «3C–H + C–Cl + H–Cl / 3 × 414 «kJ mol–1» + 324 «kJ mol–1» + 431 kJ mol–1» / 1997 «kJ» ✔
«ΔH = bond breaking – bond forming = 656 kJ – 755 kJ» = –99 «kJ» ✔
Award [3] for correct final answer.
Award [2 max] for 99 «kJ».
Examiners report
Only the very weak candidates were unable to calculate the enthalpy change correctly, eventually missing 1 mark for inverted calculations.
