DP Chemistry (first assessment 2025)

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Question 23M.2.SL.TZ1.2

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Date May 2023 Marks available [Maximum mark: 17] Reference code 23M.2.SL.TZ1.2
Level SL Paper 2 Time zone TZ1
Command term Annotate, Deduce, Explain, Outline, Sketch, State, Suggest Question number 2 Adapted from N/A
2.
[Maximum mark: 17]
23M.2.SL.TZ1.2

The periodic table is a useful tool in explaining trends of chemical behaviour.

(a.i)

Annotate and label the ground state orbital diagram of boron, using arrows to represent electrons.

[1]

Markscheme

arrows AND identifies 2s AND 2p sub orbitals ✓

 

Accept “hooks” to represent the electrons.

(a.ii)

Sketch the shapes of the occupied orbitals identified in part (a)(i).

[2]

Markscheme

 

Px,y or z can be used.
M2 cannot be awarded if labels of orbital types are missing or incorrect

Node of p orbital must be at the origin

 

(b)

Explain the decrease in first ionization energy from Li to Cs, group 1.

[2]

Markscheme

valence electron further from nucleus/«atomic» radius larger «down the group»  ✓
«electron» more shielded/ less attractive force/easier to remove ✓

(c.i)

State the electron domain geometry of the ammonia molecule.

[1]

Markscheme

tetrahedral ✓

(c.ii)

Deduce the Lewis (electron dot) structure of ammonia and sketch its 3D molecular shape.

[2]

Markscheme

 

Accept a combination of dots /crosses /lines in the Lewis structure

Lone pair not required for shape

(c.iii)

Explain, with reference to the forces between molecules, why ammonia has a higher boiling point than phosphine (PH3).

[3]

Markscheme

ammonia has intermolecular/IMF hydrogen bonds «phosphine does not» ✓
phosphine «and ammonia» dipole-dipole/London dispersion forces/instantaneous dipole attractions/Van der Waals forces ✓
hydrogen bonds stronger ✓

 

Accept converse argument.

Award 1 for stating that NH3 is more polar than phosphine so the dipole-dipole forces are stronger

(d.i)

Ammonia is manufactured by the Haber process.

N2 (g) + 3H2 (g)  2NH3 (g)  ΔHf = −92.0 kJ mol−1

Outline what is meant by dynamic equilibrium.

[1]

Markscheme

«in a closed system» the rate of the forward reaction equals the rate of the reverse reaction. ✓

(d.ii)

Deduce the Kc expression for the reaction in part (d)(i).

[1]

Markscheme

[NH3]2/([N2][H2]3) ✓

(d.iii)

The Haber process requires a catalyst. State how a catalyst functions.

[1]

Markscheme

alternate pathway AND lowers activation energy/Ea ✓

(d.iv)

Sketch a Maxwell–Boltzmann distribution curve showing the activation energies with and without a catalyst.

[2]

Markscheme

correct shape curve starting at the origin, without touching the x axis at high energy. ✓

(Ea) catalysed <(Ea) uncatalysed on x axis. ✓

 

Ignore any shading under the curve.

(d.v)

Suggest how the progress of the reaction could be monitored.

[1]

Markscheme

change in AND
volume
OR
pressure
OR
temperature
OR
concentration of H2/N2/reactants/NH/product ✓

 

Do not accept pH.
Accept any valid method.