DP Chemistry (first assessment 2025)

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Question 23M.2.HL.TZ2.7

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Date May 2023 Marks available [Maximum mark: 14] Reference code 23M.2.HL.TZ2.7
Level HL Paper 2 Time zone TZ2
Command term Deduce, Describe, Draw, Explain, Identify Question number 7 Adapted from N/A
7.
[Maximum mark: 14]
23M.2.HL.TZ2.7

Hydrogen bromide, HBr, reacts with but-1-ene

(a)

Identify the type of reaction.

[1]

Markscheme

«electrophilic» addition/AE

 

Do not accept nucleophilic addition.

(b)

Two products are possible.

(b.i)

Explain the mechanism for the formation of the major product, using curly arrows to indicate the movement of electron pairs.

[4]

Markscheme

curly arrow going from C=C to H of HBr AND curly arrow showing Br leaving ✓
correct representation of carbocation ✓
curly arrow going from lone pair/negative charge on Br− to C+
CH3CHBr(CH2CH3)/correct final product ✓

 

Award [3 max] for the correct mechanism of formation of the minor product.

(b.ii)

Explain why the mechanism results in one product being formed in greater quantities than the other.

[2]

Markscheme

carbocation with ethyl group is stabilized
OR
secondary carbocation more stable «than primary carbocation» ✓

greater electron releasing/inductive effect of «two» electron releasing alkyl groups
«on secondary carbocation compared to one on primary carbocation» ✓

 

Do not accept ‘Markovnikov’s rule’ /C with most hydrogen atoms without reference to stability of carbocation.

(c)

Draw the structure of a section of a polymer formed from three monomers of but-1-ene.

[1]

Markscheme

 

Ignore brackets and ‘n’.
Continuation bonds must be shown.
Ethyl groups do not all have to be on one side.
Accept head-to-tail or head-to-head orientation of monomer units.

(d)

Deduce the hybridization of the first two carbon atoms in but-1-ene.

[1]

Markscheme

«both» sp2

(e)

Describe the bonding between the first two carbon atoms in but-1-ene in terms of orbitals on these atoms.

[3]

Markscheme

Any three of the following:

mixing of an s AND two p orbitals forms «three» sp2 /hybrid orbitals ✓


σ bond is overlap «of sp2 orbitals» along axial/internuclear axis
OR
head-on/end-to-end overlap «of sp2 orbitals» ✓

one p electron from each C does not hybridize ✓

π bond is overlap «of p-orbitals» above and below internuclear axis
OR
sideways overlap «of parallel p orbitals» ✓

 

Accept suitable diagrams.

(f)

One isomer of C4H9Br can exist as stereoisomers. Draw the three-dimensional structures of the two stereoisomers using wedge-dash notation, clearly showing the relationship between them.

[2]

Markscheme

correct isomer ✓
mirror image shown clearly ✓

 

Do not accept Fischer projections.