DP Chemistry (first assessment 2025)
Question 23M.1A.SL.TZ2.28
Date | May 2023 | Marks available | [Maximum mark: 1] | Reference code | 23M.1A.SL.TZ2.28 |
Level | SL | Paper | 1A | Time zone | TZ2 |
Command term | Question number | 28 | Adapted from | N/A |
28.
[Maximum mark: 1]
23M.1A.SL.TZ2.28
Which species is the oxidizing agent?
14H+ (aq) + 2Mn2+ (aq) + 5BiO3− (aq) → 2MnO4− (aq) + 5Bi3+ (aq) + 7H2O (l)
A. H+ (aq)
B. Mn2+ (aq)
C. BiO3− (aq)
D. MnO4− (aq)
[1]
Markscheme
C