DP Physics (first assessment 2025)

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Question 19M.1A.SL.TZ1.23

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Date May 2019 Marks available [Maximum mark: 1] Reference code 19M.1A.SL.TZ1.23
Level SL Paper 1A Time zone TZ1
Command term Question number 23 Adapted from N/A
23.
[Maximum mark: 1]
19M.1A.SL.TZ1.23

The carbon isotope 14 6 C is radioactive. It decays according to the equation

14 6 C →  14 7 N + X + Y

 

What are X and Y?

[1]

Markscheme

B

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This question was well answered by candidates, with a high discrimination index.

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