DP Physics (first assessment 2025)
Question 22N.2.SL.TZ0.6b.i
Date | November 2022 | Marks available | [Maximum mark: 2] | Reference code | 22N.2.SL.TZ0.6b.i |
Level | SL | Paper | 2 | Time zone | TZ0 |
Command term | Calculate | Question number | b.i | Adapted from | N/A |
b.i.
[Maximum mark: 2]
22N.2.SL.TZ0.6b.i
(b.i)
Calculate, in MeV, the energy released in this decay.
[2]
Markscheme
(mpolonium − mlead − mα)c2 OR (209.93676 − 205.92945 − 4.00151)
OR
mass difference = 5.8 × 10−3 ✓
conversion to MeV using 931.5 to give 5.4 «MeV» ✓
Allow ECF from MP1.
Award [2] for a BCA.
Award [1] for 8.6 x 10−13 J.
Examiners report
Generally, well answered. There were quite a few who fell into the trap of multiplying by an unnecessary c2 as they were not sure of the significance of the unit of u.
