DP Physics (first assessment 2025)

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Question SPM.2.SL.TZ0.6

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Date May Specimen-2023 Marks available [Maximum mark: 5] Reference code SPM.2.SL.TZ0.6
Level SL Paper 2 Time zone TZ0
Command term Calculate, Suggest Question number 6 Adapted from N/A
6.
[Maximum mark: 5]
SPM.2.SL.TZ0.6

Small pieces of solid paraffin with a total mass of 30 g at a temperature of 42 °C are mixed with 150 g of liquid paraffin at a temperature of 240 °C. The mixture is stirred until an equilibrium temperature is reached.

The following data for paraffin are available:

Specific heat capacity of solid paraffin = 0.7 kJ kg−1 K−1
Specific heat capacity of liquid paraffin = 2.13 kJ kg−1 K−1
Specific latent heat of fusion of paraffin = 220 kJ kg−1
Melting point of paraffin = 47 °C

(a)

Calculate the theoretical equilibrium temperature of the mixture.

[3]

Markscheme

0.030×0.7×103×5+0.030×220×103+0.030×2.13×103T-47

=0.150×2.13×103240-T

One heat capacity term correctly substituted ✓

latent heat correctly substituted 0.030×220×103 ✓

T=190 «°C» ✓

(b)

When the experiment was carried out, the equilibrium temperature of the mixture was found to be different from the theoretical value. 

Suggest the reason for this difference.

[2]

Markscheme

Experimental temperature will be lower ✓

Heat loss to the environment ✓