Question 23M.2.HL.TZ1.3
| Date | May 2023 | Marks available | [Maximum mark: 15] | Reference code | 23M.2.HL.TZ1.3 |
| Level | HL | Paper | 2 | Time zone | TZ1 |
| Command term | Calculate, Determine, Explain, Show, Sketch, State | Question number | 3 | Adapted from | N/A |
A transverse water wave travels to the right. The diagram shows the shape of the surface of the water at time t = 0. P and Q show two corks floating on the surface.
State what is meant by a transverse wave.
[1]
«A wave where the» displacement of particles/oscillations of particles/movement of particles/vibrations of particles is perpendicular/normal to the direction of energy transfer/wave travel/wave velocity/wave movement/wave propagation ✓
Allow medium, material, water, molecules, or atoms for particles.
The frequency of the wave is 0.50 Hz. Calculate the speed of the wave.
[1]
v = «0.50 × 16 =» 8.0 «m s−1» ✓
Sketch on the diagram the position of P at time t = 0.50 s.
[1]
P at (8, 1.2) ✓
Show that the phase difference between the oscillations of the two corks is radians.
[1]
ALTERNATIVE 1
Phase difference is × ✓
«= » ✓
ALTERNATIVE 2
One wavelength/period represents «phase difference» of 2 and «corks» are ½ wavelength/period apart so phase difference is /OWTTE ✓
Monochromatic light is incident on two very narrow slits. The light that passes through the slits is observed on a screen. M is directly opposite the midpoint of the slits. represents the displacement from M in the direction shown.
A student argues that what will be observed on the screen will be a total of two bright spots opposite the slits. Explain why the student’s argument is incorrect.
[2]
light acts as a wave «and not a particle in this situation» ✓
light at slits will diffract / create a diffraction pattern ✓
light passing through slits will interfere / create an interference pattern «creating bright and dark spots» ✓
The graph shows the actual variation with displacement from M of the intensity of the light on the screen. is the intensity of light at the screen from one slit only.
Explain why the intensity of light at = 0 is 4 .
[2]
The amplitude «at x = 0» will be doubled ✓
intensity is proportional to amplitude squared / ∝ A2 ✓
The slits are separated by a distance of 0.18 mm and the distance to the screen is 2.2 m. Determine, in m, the wavelength of light.
[2]
Use of s = = OR s = = ✓
= « =» 4.6 × 10−7 «m» ✓
The two slits are replaced by many slits of the same separation. State one feature of the intensity pattern that will remain the same and one that will change.
Stays the same:
Changes:
[2]
Stays the same: Position/location of maxima/distance/separation between maxima «will be the same» / OWTTE ✓
Changes: Intensity/brightness/width/sharpness «of maxima will change»/ OWTTE ✓
Allow other phrasing for maxima (fringes, spots, etc).
Two sources are viewed though a single slit. The graph shows the diffraction pattern of one source.
Sketch, on the axes, the diffraction pattern of the second source when the images of the two sources are just resolved according to the Rayleigh criterion.
[1]
Maximum coinciding with first minimum AND minimum coinciding with maximum✓
Allow a graph drawn to the left of the original graph with these same characteristics.
Centaurus A is a galaxy a distance of 1.1 × 1023 m away. A radio telescope of diameter 300 m operating at a wavelength of 3.2 cm is used to observe the galaxy. Determine the minimum size of the radio emitting region of the galaxy that can be resolved by this telescope.
[2]
ALTERNATIVE 1
= 1.22 × therefore d = ✓
«d 1.22 × » = 1.4 × 1019 «m» ✓
ALTERNATIVE 2
θ = «1.22 = 1.22 × =» 1.3 × 10−4 «radians» ✓
d = «(1.1 × 1023)(1.3 × 10−4) =» 1.4 × 1019 «m» ✓