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Question 23M.2.HL.TZ2.9bii

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Date May 2023 Marks available [Maximum mark: 1] Reference code 23M.2.HL.TZ2.9bii
Level HL Paper 2 Time zone TZ2
Command term Calculate Question number ii Adapted from N/A
ii.
[Maximum mark: 1]
23M.2.HL.TZ2.9bii
(ii)

Calculate the difference between the magnitudes of the total energy transfers in parts (a) and (b).

[1]

Markscheme

Difference = 2.6175 – (1.76656 +0.84376) = 2.6175 – 2.61032 = 0.007195 «MeV»

OR

Difference = 2.6175 – (1.59587 +1.01445) = 2.61032 = 0.007195 «MeV» ✓

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