DP Physics (first assessment 2025)

Test builder »

Question 23M.2.SL.TZ2.1d

Select a Test
Date May 2023 Marks available [Maximum mark: 3] Reference code 23M.2.SL.TZ2.1d
Level SL Paper 2 Time zone TZ2
Command term Calculate Question number d Adapted from N/A
d.
[Maximum mark: 3]
23M.2.SL.TZ2.1d
(d)

After a second bounce, the bottle rotates about its centre of mass. The bottle rotates at 0.35 revolutions per second.

The centre of mass of the bottle is halfway between the base and the top of the bottle. Assume that the velocity of the centre of mass is zero.

Calculate the linear speed of the top of the bottle.

[3]

Markscheme

ALTERNATIVE 1

ω = 2π(0.35) «=2.20 rad s−1» ✓
Use of v = 0.14ω ✓
0.31 «m s−1» ✓

 

ALTERNATIVE 2

T = 10.35 «= 2.9 s» ✓

V = 2π(0.14)T  OR  v20.14 = 4π2(0.14)T2 ✓

v = 0.31 «m s−1» ✓

 

Award [3] for BCA

Syllabus sections