Question 23M.2.SL.TZ1.9d

ALTERNATIVE 1

$Q=\mathrm{\Delta }U=\frac{3}{2}{V}_{\text{C}}\mathrm{\Delta }P$ ✓

$Q=$«$\frac{3}{2}$ × 3.33 × 10⁻² × (3.00 × 10⁴ − 4.60 × 10³)» = 1268.7 ≈ 1270 «J» ✓

Award [2] for BCA.

Accept negative values.

ALTERNATIVE 2

$Rn=\frac{5\times {10}^5\times 2\times {10}^{-3}}{602}=1.66$  OR  T_c = 4.6 × 10³ × 3.33 × 10⁻² × 1.66 = 92.2  ✓

$\mathrm{\Delta }U=\frac{3}{2}\times 1.661\times (602-92.21)=1270$ «J» ✓

Award MP1 if T_c = 92 taken from (e)