DP Physics (first assessment 2025)

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Question 22M.2.SL.TZ1.d

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Date May 2022 Marks available [Maximum mark: 4] Reference code 22M.2.SL.TZ1.d
Level SL Paper 2 Time zone TZ1
Command term Determine Question number d Adapted from N/A
d.
[Maximum mark: 4]
22M.2.SL.TZ1.d

After the load has hit the floor, the box travels a further 0.35 m along the ramp before coming to rest. Determine the average frictional force between the box and the surface of the ramp.

[4]

Markscheme

ALTERNATIVE 1

«v2=u2+2as⇒0=2.12-2a×0.35» leading to a = 6.3 «m s-2»

OR

« x=1/2u+vt » leading to t = 0.33 « s » ✓


Fnet = « ma=1.5×6.3 = » 9.45 «N» ✓

Weight down ramp = 1.5 x 9.8 x sin(30) = 7.4 «N» ✓

friction force = net force – weight down ramp = 2.1 «N» ✓

 

ALTERNATIVE 2

kinetic energy initial = work done to stop 0.5 x 1.5 x (2.1)2 = FNET x 0.35 ✓

Fnet = 9.45 «N» ✓

Weight down ramp = 1.5 x 9.8 x sin(30) = 7.4 «N» ✓

friction force = net force – weight down ramp = 2.1 «N» ✓

 

Accept 1.95 N from g = 10 m s-2.
Accept 2.42 N from u = 2.14 m s-1.

Examiners report

Candidates struggled with this question. Very few drew a clear free-body diagram and many simply calculated the acceleration of the box from the given information and used this to calculate the net force on the box, confusing this with the frictional force.

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