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Date May Example question Marks available 3 Reference code EXM.1.AHL.TZ0.10
Level Additional Higher Level Paper Paper 1 Time zone Time zone 0
Command term Find Question number 10 Adapted from N/A

Question

Let A ( 3 2 k 4 ) and B = ( 2 2 1 3 ) . Find, in terms of k ,

2B.

[3]
a.

det (2B).

[3]
b.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

 

2 ( 6 4 2 k 8 )           (A1)

2− B =  ( 4 2 2 k 1 5 )         A2   N3

[3 marks]

a.

Evidence of using the definition of determinant                    (M1)

Correct substitution                (A1)

eg 4(5) − 2(2 k − 1), 20 − 2(2 k 1), 20 − 4 k  + 2

det (2− B) = 22 − 4 k                A1  N3

[3 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 1—Number and algebra » AHL 1.14—Introduction to matrices
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Topic 1—Number and algebra

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