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Date May Example question Marks available 3 Reference code EXM.2.AHL.TZ0.11
Level Additional Higher Level Paper Paper 2 Time zone Time zone 0
Command term Solve and Hence Question number 11 Adapted from N/A

Question

Let M = ( 2 1 2 1 ) .

Write down the determinant of M.

[1]
a.

 Write down M−1.

[2]
b.

Hence solve M ( x y ) = ( 4 8 ) .

 

[3]
c.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

det M = −4       A1  N1

[1 mark]

a.

M−1 = 1 4 ( 1 1 2 2 ) ( = ( 1 4 1 4 1 2 1 2 ) )       A1A1 N2

Note:   Award A1 for  1 4  and A1 for the correct matrix.   

[2 marks]

b.

X = M−1 ( 4 8 )   ( X = 1 4 ( 1 1 2 2 ) ( 4 8 ) )       M1

( 3 2 )      ( x = 3 y = 2 )      A1A1   N0

 

Note: Award no marks for an algebraic solution of the system 2 x + y = 4 2 x y = 8 .            

[3 marks]

c.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.

Syllabus sections

Topic 1—Number and algebra » AHL 1.14—Introduction to matrices
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Topic 1—Number and algebra

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