User interface language: English | Español

Date November Example question Marks available 1 Reference code EXN.1.SL.TZ0.7
Level Standard Level Paper Paper 1 Time zone Time zone 0
Command term Find Question number 7 Adapted from N/A

Question

Consider the curve y=x2-4x+2.

Find an expression for dydx.

[1]
a.

Show that the normal to the curve at the point where x=1 is 2y-x+3=0.

[6]
b.

Markscheme

* This sample question was produced by experienced DP mathematics senior examiners to aid teachers in preparing for external assessment in the new MAA course. There may be minor differences in formatting compared to formal exam papers.

dydx=2x-4      A1

  

[1 mark]

a.

Gradient at x=1 is -2         M1

Gradient of normal is 12         A1

When x=1  y=1-4+2=-1          (M1)A1

 

EITHER

y+1=12x-1         M1

2y+2=x-1  or  y+1=12x-12         A1

 

OR

-1=12×1+c         M1

y=12x-32         A1

 

THEN

2y-x+3=0         AG

 

[6 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 5—Calculus » SL 5.3—Differentiating polynomials, n E Z
Show 146 related questions
Topic 5—Calculus » SL 5.4—Tangents and normal
Topic 5—Calculus

View options