DP Biology (last assessment 2024)
Question 18M.2.SL.TZ1.3a
Date | May 2018 | Marks available | [Maximum mark: 3] | Reference code | 18M.2.SL.TZ1.3a |
Level | SL | Paper | 2 | Time zone | TZ1 |
Command term | Explain | Question number | a | Adapted from | N/A |
a.
[Maximum mark: 3]
18M.2.SL.TZ1.3a
(a)
Using the Punnett grid, explain how two parents can have children with any of the different ABO blood groups.
[3]
Markscheme
a. correct gametes of one parent as IA AND i in header line/column
AND
correct gametes of other parent as IB AND i in header column/line
b. correct corresponding genotypes in inner squares as IAIB, IAi, IBi, ii
c. corresponding phenotypes of children identified as AB, A, B and O
d. ratio of phenotypes is 1:1:1:1 OWTTE
Allow ECF.
