Syllabus sections » |
3.4 Inheritance
Description
Nature of science: Making quantitative measurements with replicates to ensure reliability. Mendel’s genetic crosses with pea plants generated numerical data. (3.2) |
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Understandings:
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Theory of knowledge:
Syllabus and cross-curricular links: Biology Topic 1.6 Cell division Aims:
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Directly related questions
- 17N.1.HL.TZ0.12: A dominant autosomal allele for lactase persistence allows humans to digest milk as adults....
- 17N.1.SL.TZ0.16: An allele for lactase persistence allows humans to digest milk as adults. People who lack this...
- 17N.1.HL.TZ0.12: A dominant autosomal allele for lactase persistence allows humans to digest milk as adults....
- 18M.2.SL.TZ1.3a: Using the Punnett grid, explain how two parents can have children with any of the different ABO...
- 17N.1.SL.TZ0.16: An allele for lactase persistence allows humans to digest milk as adults. People who lack this...
- 18M.1.HL.TZ1.40: What contributes to the total DNA content of a zygote?
- 18M.1.HL.TZ1.40: What contributes to the total DNA content of a zygote?
- 18M.1.SL.TZ1.21: What explains the presence in living humans of DNA sections which are identical to DNA found in...
- 18M.1.SL.TZ1.21: What explains the presence in living humans of DNA sections which are identical to DNA found in...
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18M.2.HL.TZ1.3b.i:
Distinguish between sex-linked genes and genes with linked loci.
- 18M.2.SL.TZ1.3a: Using the Punnett grid, explain how two parents can have children with any of the different ABO...
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18M.2.HL.TZ1.3b.i:
Distinguish between sex-linked genes and genes with linked loci.
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18M.2.HL.TZ1.b.i:
Distinguish between sex-linked genes and genes with linked loci.
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18M.2.HL.TZ1.3b.ii:
Outline how it can be shown that the genes for shell base colour (Cc) and presence or absence of bands (Bb) are linked.
- 18M.2.SL.TZ1.a: Using the Punnett grid, explain how two parents can have children with any of the different ABO...
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18M.1.HL.TZ2.20:
Nail patella syndrome is a rare disease that causes abnormalities of the nails and some bones. Its alleles are linked to the blood group alleles on the same chromosome. The pedigree chart shows the inheritance of these two characteristics over three generations.
[Source: Copyright © 1998. Phillip McClean]
Which descendant represents a recombinant phenotype?
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18M.2.HL.TZ1.3b.ii:
Outline how it can be shown that the genes for shell base colour (Cc) and presence or absence of bands (Bb) are linked.
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18M.2.HL.TZ1.b.ii:
Outline how it can be shown that the genes for shell base colour (Cc) and presence or absence of bands (Bb) are linked.
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18M.2.HL.TZ2.3b:
The genes for cystic fibrosis and blood group are not linked. Two parents are heterozygous for cystic fibrosis. One parent has blood group O and the other has blood group AB. Using a Punnett square, determine the probability that their child will have both cystic fibrosis and blood group A.
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18M.2.HL.TZ2.3b:
The genes for cystic fibrosis and blood group are not linked. Two parents are heterozygous for cystic fibrosis. One parent has blood group O and the other has blood group AB. Using a Punnett square, determine the probability that their child will have both cystic fibrosis and blood group A.
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18M.2.HL.TZ2.b:
The genes for cystic fibrosis and blood group are not linked. Two parents are heterozygous for cystic fibrosis. One parent has blood group O and the other has blood group AB. Using a Punnett square, determine the probability that their child will have both cystic fibrosis and blood group A.
- 18M.1.SL.TZ2.15: What is the percentage risk of a child inheriting Huntington’s disease if only one parent has the...
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18M.1.HL.TZ2.20:
Nail patella syndrome is a rare disease that causes abnormalities of the nails and some bones. Its alleles are linked to the blood group alleles on the same chromosome. The pedigree chart shows the inheritance of these two characteristics over three generations.
[Source: Copyright © 1998. Phillip McClean]
Which descendant represents a recombinant phenotype?
- 18N.1.SL.TZ0.12: The image shows the chromosomes in four cells of an insect at the end of meiosis. What is the...
- 18N.2.HL.TZ0.7a: Isolated communities in rural Finland, Hungary and some of the Scottish islands have a high...
- 18N.1.SL.TZ0.12: The image shows the chromosomes in four cells of an insect at the end of meiosis. What is the...
- 18N.1.SL.TZ0.14: A human gene has two alleles. One allele, P, is dominant over the recessive allele p. Embryos...
- 18M.1.SL.TZ2.15: What is the percentage risk of a child inheriting Huntington’s disease if only one parent has the...
- 18N.2.HL.TZ0.7a: Isolated communities in rural Finland, Hungary and some of the Scottish islands have a high...
- 18N.2.SL.TZ0.6a: Isolated communities in rural Finland, Hungary and some of the Scottish islands have a high...
- 18N.1.SL.TZ0.14: A human gene has two alleles. One allele, P, is dominant over the recessive allele p. Embryos...
- 18N.2.HL.TZ0.a: Isolated communities in rural Finland, Hungary and some of the Scottish islands have a high...
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19M.1.SL.TZ2.14:
The pedigree chart shows a family affected by cystic fibrosis.
[Source: © International Baccalaureate Organization 2019]
What is the genotype of the affected boy’s father?
A. AA only
B. Either AA or Aa
C. Aa only
D. aa only
- 18N.1.SL.TZ0.15: In cats, black coat colour is dominant over gray. A female black cat, whose mother is gray, mates...
- 18N.1.SL.TZ0.15: In cats, black coat colour is dominant over gray. A female black cat, whose mother is gray, mates...
- 18N.2.SL.TZ0.6a: Isolated communities in rural Finland, Hungary and some of the Scottish islands have a high...
- 18N.2.SL.TZ0.a: Isolated communities in rural Finland, Hungary and some of the Scottish islands have a high...
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19M.1.SL.TZ1.15:
Creeper in chickens is a condition in which the chickens are born with very short legs. The creeper allele (C) is dominant over the normal allele (c). Embryos which are homozygous for the dominant allele fail to develop into viable chickens and die before they hatch. What phenotypic ratio would you expect in the live offspring of a cross between two creeper chickens?
A. All creeper
B. 1 creeper; 2 normal
C. 2 creeper; 1 normal
D. 3 creeper; 1 normal
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19M.1.SL.TZ2.14:
The pedigree chart shows a family affected by cystic fibrosis.
[Source: © International Baccalaureate Organization 2019]
What is the genotype of the affected boy’s father?
A. AA only
B. Either AA or Aa
C. Aa only
D. aa only
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19M.1.SL.TZ1.15:
Creeper in chickens is a condition in which the chickens are born with very short legs. The creeper allele (C) is dominant over the normal allele (c). Embryos which are homozygous for the dominant allele fail to develop into viable chickens and die before they hatch. What phenotypic ratio would you expect in the live offspring of a cross between two creeper chickens?
A. All creeper
B. 1 creeper; 2 normal
C. 2 creeper; 1 normal
D. 3 creeper; 1 normal
- 19M.2.SL.TZ2.4b: Explain one cause of mutation.
- 19M.1.SL.TZ2.15: The children in a family have blood groups A, B and O. What are the genotypes of their...
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19M.1.SL.TZ1.16:
Which pedigree chart is consistent with the inheritance of red-green colour blindness?
[Source: © International Baccalaureate Organization 2019]
- 19M.1.SL.TZ2.15: The children in a family have blood groups A, B and O. What are the genotypes of their...
- 19M.2.SL.TZ2.4b: Explain one cause of mutation.
- 19M.2.SL.TZ2.b: Explain one cause of mutation.
- 19N.2.SL.TZ0.6b: Outline how two parents could have a child with any of the four ABO blood groups.
- 19M.2.HL.TZ2.7b: Mendel found the same pattern of inheritance in all the crosses that he performed. Outline, with...
- 19M.2.HL.TZ2.7b: Mendel found the same pattern of inheritance in all the crosses that he performed. Outline, with...
- 19M.2.HL.TZ2.b: Mendel found the same pattern of inheritance in all the crosses that he performed. Outline, with...
- 19N.2.HL.TZ0.7b: Outline how two parents could have a child with any of the four ABO blood groups.
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19M.1.SL.TZ1.16:
Which pedigree chart is consistent with the inheritance of red-green colour blindness?
[Source: © International Baccalaureate Organization 2019]
- 19N.2.HL.TZ0.2a: State the type of inheritance shown.
- 19N.2.SL.TZ0.6b: Outline how two parents could have a child with any of the four ABO blood groups.
- 19N.2.HL.TZ0.2a: State the type of inheritance shown.
- 19N.2.HL.TZ0.a: State the type of inheritance shown.
- 19N.2.HL.TZ0.7b: Outline how two parents could have a child with any of the four ABO blood groups.
- 19N.2.HL.TZ0.b: Outline how two parents could have a child with any of the four ABO blood groups.
- 19N.2.SL.TZ0.b: Outline how two parents could have a child with any of the four ABO blood groups.
- 19N.1.SL.TZ0.15: A variety of Pelargonium has yellow leaves. When plants of this variety are crossed, the...
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19N.1.HL.TZ0.12:
The pedigree chart shows the inheritance of hemophilia in some of the descendants of Queen Victoria. Which letter points to a family member certain to be heterozygous?
[Source: © International Baccalaureate Organization 2019]
- 19N.1.SL.TZ0.15: A variety of Pelargonium has yellow leaves. When plants of this variety are crossed, the...
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19N.1.HL.TZ0.12:
The pedigree chart shows the inheritance of hemophilia in some of the descendants of Queen Victoria. Which letter points to a family member certain to be heterozygous?
[Source: © International Baccalaureate Organization 2019]
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19N.1.SL.TZ0.16:
A pair of alleles controls the secretion of antigens corresponding to blood group in saliva. Examine the pedigree chart.
[Source: © International Baccalaureate Organization 2019]
Based on this pedigree chart, which best describes the allele conferring antigen secretion in saliva?
A. Dominant
B. Recessive
C. Sex-linked
D. Co-dominant
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19N.1.SL.TZ0.16:
A pair of alleles controls the secretion of antigens corresponding to blood group in saliva. Examine the pedigree chart.
[Source: © International Baccalaureate Organization 2019]
Based on this pedigree chart, which best describes the allele conferring antigen secretion in saliva?
A. Dominant
B. Recessive
C. Sex-linked
D. Co-dominant
- 20N.1.SL.TZ0.13: In the pedigree chart, individuals affected by a genetic disease are shown as shaded symbols....
- 20N.1.SL.TZ0.13: In the pedigree chart, individuals affected by a genetic disease are shown as shaded symbols....
- 20N.1.SL.TZ0.14: Tall heterozygous pea plants were crossed and the resulting seeds grown. Out of 360 plants, 270...
- 20N.1.SL.TZ0.14: Tall heterozygous pea plants were crossed and the resulting seeds grown. Out of 360 plants, 270...
- 20N.1.SL.TZ0.15: What are all the possible phenotypes of children born to a mother with blood group AB and a...
- 20N.1.SL.TZ0.15: What are all the possible phenotypes of children born to a mother with blood group AB and a...
- 21M.1.SL.TZ1.18: Which genotype would be normally found in a gamete? A. Rr B. RS C. rStt D. TUt
- 21M.1.SL.TZ2.15: A woman with blood type A has three children with a man who has blood type AB. The first child...
- 21M.1.SL.TZ1.18: Which genotype would be normally found in a gamete? A. Rr B. RS C. rStt D. TUt
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21M.2.HL.TZ1.7a:
Outline the inheritance of blood types in the ABO blood system in humans.
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21M.2.HL.TZ1.7a:
Outline the inheritance of blood types in the ABO blood system in humans.
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21M.2.HL.TZ1.a:
Outline the inheritance of blood types in the ABO blood system in humans.
- 21M.1.SL.TZ2.15: A woman with blood type A has three children with a man who has blood type AB. The first child...
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21M.2.HL.TZ2.5b:
Outline how sperm are produced from diploid cells in the testis and how this production can be sustained over many decades of adult life.
- 21N.1.SL.TZ0.15: In humans, male pattern baldness is caused by a recessive sex-linked gene found only on the X...
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21M.2.HL.TZ2.5b:
Outline how sperm are produced from diploid cells in the testis and how this production can be sustained over many decades of adult life.
-
21M.2.HL.TZ2.b:
Outline how sperm are produced from diploid cells in the testis and how this production can be sustained over many decades of adult life.
- 21N.1.SL.TZ0.15: In humans, male pattern baldness is caused by a recessive sex-linked gene found only on the X...
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21N.2.HL.TZ0.2a.i:
Draw a Punnett square to show all the possible genotypes of Queen Victoria’s children.
- 21N.1.HL.TZ1.12: Huntington’s disease can develop in middle age and leads to death of brain cells. It is carried...
- 21N.1.HL.TZ1.12: Huntington’s disease can develop in middle age and leads to death of brain cells. It is carried...
-
21N.2.HL.TZ0.2a.i:
Draw a Punnett square to show all the possible genotypes of Queen Victoria’s children.
-
21N.2.HL.TZ0.a.i:
Draw a Punnett square to show all the possible genotypes of Queen Victoria’s children.
- 22M.1.SL.TZ1.16: Huntington’s disease is an autosomal dominant genetic disease. What are the chances of two...
- 21N.2.HL.TZ0.2a.ii: Deduce the genotype of Queen Victoria’s daughter Alice.
- 21N.2.HL.TZ0.2a.ii: Deduce the genotype of Queen Victoria’s daughter Alice.
- 21N.2.HL.TZ0.a.ii: Deduce the genotype of Queen Victoria’s daughter Alice.
- 22M.1.SL.TZ1.16: Huntington’s disease is an autosomal dominant genetic disease. What are the chances of two...
- 22M.2.SL.TZ1.4a: State the probability that Edward had hemophilia.
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22N.2.SL.TZ0.4a:
Draw the symbol for individual X on the diagram.
- 22M.2.SL.TZ1.4a: State the probability that Edward had hemophilia.
- 22M.2.SL.TZ1.a: State the probability that Edward had hemophilia.
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22M.2.SL.TZ1.4b:
Explain the reasons for none of the females in the pedigree chart having hemophilia.
-
22M.2.SL.TZ1.4b:
Explain the reasons for none of the females in the pedigree chart having hemophilia.
-
22M.2.SL.TZ1.b:
Explain the reasons for none of the females in the pedigree chart having hemophilia.
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22M.2.SL.TZ2.6b:
A family has a history of hemophilia that is caused by a sex-linked recessive allele. A woman from this family is a carrier and marries a man who does not have the allele. Showing your working, determine the probability of their children having the disease.
-
22M.2.SL.TZ2.6b:
A family has a history of hemophilia that is caused by a sex-linked recessive allele. A woman from this family is a carrier and marries a man who does not have the allele. Showing your working, determine the probability of their children having the disease.
-
22M.2.SL.TZ2.b:
A family has a history of hemophilia that is caused by a sex-linked recessive allele. A woman from this family is a carrier and marries a man who does not have the allele. Showing your working, determine the probability of their children having the disease.
- 22M.1.SL.TZ2.15: The pedigree chart shows the inheritance of hemochromatosis, a genetic disease which causes an...
- 22M.1.SL.TZ2.15: The pedigree chart shows the inheritance of hemochromatosis, a genetic disease which causes an...
- 22M.1.SL.TZ2.17: A group of students used quadrat sampling to gather data on the presence of two plant species in...
- 22M.1.SL.TZ2.17: A group of students used quadrat sampling to gather data on the presence of two plant species in...
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22N.1.SL.TZ0.15:
A couple have four children whose blood groups are A, B and AB. What is the likely combination of the parents’ genotypes?
A. IAi and IBi
B. IAi and IBIB
C. IAIB and ii
D. IAIA and IBIB
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22N.2.SL.TZ0.4a:
Draw the symbol for individual X on the diagram.
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22N.1.SL.TZ0.15:
A couple have four children whose blood groups are A, B and AB. What is the likely combination of the parents’ genotypes?
A. IAi and IBi
B. IAi and IBIB
C. IAIB and ii
D. IAIA and IBIB
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22N.2.SL.TZ0.a:
Draw the symbol for individual X on the diagram.
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22N.2.SL.TZ0.4b:
Calculate the probability of male Y having an allele for the disorder.
-
22N.2.SL.TZ0.4b:
Calculate the probability of male Y having an allele for the disorder.
-
22N.2.SL.TZ0.b:
Calculate the probability of male Y having an allele for the disorder.
- 22N.2.SL.TZ0.4c: Explain how the information in the box labelled B indicates that the gene is not sex-linked.
- 22N.2.SL.TZ0.4c: Explain how the information in the box labelled B indicates that the gene is not sex-linked.
- 22N.2.SL.TZ0.c: Explain how the information in the box labelled B indicates that the gene is not sex-linked.
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23M.1.HL.TZ1.34:
A total of 271 164 people were tested for blood groups in Mexico. The pie chart summarizes the ABO blood group distribution.
[Source: Canizalez-Román, A. et al., 2018. Blood Groups Distribution and Gene Diversity
of the ABO and Rh (D) Loci in the Mexican Population.
BioMed Research International, (Article ID 1925619).
http://dx.doi.org/10.1155/2018/1925619. Public domain.]What can be concluded from the ABO blood group distribution in Mexico?
A. Allele frequencies are not the same for all blood group alleles.
B. The majority of the Mexican population shows a co-dominant phenotype.
C. Most of the Mexican population can receive blood from all blood groups.
D. Only 2 % of the Mexican population have a heterozygous genotype for blood groups.
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23M.1.HL.TZ1.34:
A total of 271 164 people were tested for blood groups in Mexico. The pie chart summarizes the ABO blood group distribution.
[Source: Canizalez-Román, A. et al., 2018. Blood Groups Distribution and Gene Diversity
of the ABO and Rh (D) Loci in the Mexican Population.
BioMed Research International, (Article ID 1925619).
http://dx.doi.org/10.1155/2018/1925619. Public domain.]What can be concluded from the ABO blood group distribution in Mexico?
A. Allele frequencies are not the same for all blood group alleles.
B. The majority of the Mexican population shows a co-dominant phenotype.
C. Most of the Mexican population can receive blood from all blood groups.
D. Only 2 % of the Mexican population have a heterozygous genotype for blood groups.
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23M.2.HL.TZ1.5a:
Explain the conclusion that can be drawn from Cross 1.
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23M.2.SL.TZ1.5a:
Explain the conclusion that can be drawn from Cross 1.
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23M.1.HL.TZ2.13:
The pedigree chart shows the inheritance of three generations of Duane syndrome, a condition caused by a dominant allele that affects alignment of the eyes.
[Source: Yang, M.-M., Ho, M. et al., 2013. Pedigree of a Chinese family with Duane retraction syndrome. [diagram online]
Available at: https://www.researchgate.net/figure/Pedigree-of-a-Chinese-family-with-Duane-retraction-syndrome-
Squares-men-circles_fig1_236921765 [Accessed 5 October 2021]. Public domain.]If individuals II:1 and II:2 had a third child, what is the probability that the child would have Duane syndrome?
A. 25 %
B. 50 %
C. 75 %
D. 100 %
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23M.2.HL.TZ1.5a:
Explain the conclusion that can be drawn from Cross 1.
-
23M.2.HL.TZ1.a:
Explain the conclusion that can be drawn from Cross 1.
-
23M.2.SL.TZ1.5a:
Explain the conclusion that can be drawn from Cross 1.
-
23M.2.SL.TZ1.a:
Explain the conclusion that can be drawn from Cross 1.
- 23M.2.HL.TZ2.4ai: State with a reason whether pangolins are autotrophic or heterotrophic.
- 23M.2.HL.TZ2.4ai: State with a reason whether pangolins are autotrophic or heterotrophic.
- 23M.2.HL.TZ2.i: State with a reason whether pangolins are autotrophic or heterotrophic.
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23M.1.SL.TZ2.16:
The pedigree chart shows the inheritance of three generations of Duane syndrome, a condition caused by a dominant allele that affects alignment of the eyes.
[Source: Yang, M.-M., Ho, M. et al., 2013. Pedigree of a Chinese family with Duane retraction syndrome. [diagram online]
Available at: https://www.researchgate.net/figure/Pedigree-of-a-Chinese-family-with-Duane-retraction-syndrome-
Squares-men-circles_fig1_236921765 [Accessed 5 October 2021]. Public domain.]If individuals II:1 and II:2 had a third child, what is the probability that the child would have Duane syndrome?
A. 25 %
B. 50 %
C. 75 %
D. 100 %
-
23M.1.SL.TZ2.16:
The pedigree chart shows the inheritance of three generations of Duane syndrome, a condition caused by a dominant allele that affects alignment of the eyes.
[Source: Yang, M.-M., Ho, M. et al., 2013. Pedigree of a Chinese family with Duane retraction syndrome. [diagram online]
Available at: https://www.researchgate.net/figure/Pedigree-of-a-Chinese-family-with-Duane-retraction-syndrome-
Squares-men-circles_fig1_236921765 [Accessed 5 October 2021]. Public domain.]If individuals II:1 and II:2 had a third child, what is the probability that the child would have Duane syndrome?
A. 25 %
B. 50 %
C. 75 %
D. 100 %
-
23M.1.HL.TZ2.13:
The pedigree chart shows the inheritance of three generations of Duane syndrome, a condition caused by a dominant allele that affects alignment of the eyes.
[Source: Yang, M.-M., Ho, M. et al., 2013. Pedigree of a Chinese family with Duane retraction syndrome. [diagram online]
Available at: https://www.researchgate.net/figure/Pedigree-of-a-Chinese-family-with-Duane-retraction-syndrome-
Squares-men-circles_fig1_236921765 [Accessed 5 October 2021]. Public domain.]If individuals II:1 and II:2 had a third child, what is the probability that the child would have Duane syndrome?
A. 25 %
B. 50 %
C. 75 %
D. 100 %
- 23M.1.HL.TZ2.32: In the fruit fly Drosophila, the alleles for red eyes and brown bodies are dominant to the...
-
23M.1.HL.TZ1.10:
Scientists sequenced the genes in each chromosome of chimpanzees (Pan troglodytes) and humans (Homo sapiens). The graph shows the mean divergence between the genes of these species by chromosome.
[Source: Material from: Mikkelsen, T.S. et al, Initial sequence of the chimpanzee genome and
comparison with the human genome, 2005 Nature, reproduced with permission of SNCSC.]
What can be deduced from this data?
A. Autosomes are more similar than Y chromosomes.B. There is the same number of chromosomes in humans and chimpanzees.
C. Humans are more closely related to chimpanzees than to other species.
D. Smaller chromosomes are more similar than larger chromosomes.
-
23M.1.SL.TZ1.14:
Scientists sequenced the genes in each chromosome of chimpanzees (Pan troglodytes) and humans (Homo sapiens). The graph shows the mean divergence between the genes of these species by chromosome.
[Source: Material from: Mikkelsen, T.S. et al, Initial sequence of the chimpanzee genome and
comparison with the human genome, 2005 Nature, reproduced with permission of SNCSC.]
What can be deduced from this data?
A. Autosomes are more similar than Y chromosomes.B. There is the same number of chromosomes in humans and chimpanzees.
C. Humans are more closely related to chimpanzees than to other species.
D. Smaller chromosomes are more similar than larger chromosomes.
- 23M.1.HL.TZ2.32: In the fruit fly Drosophila, the alleles for red eyes and brown bodies are dominant to the...
-
23M.2.SL.TZ2.2a:
State how many chromosomes there would be in male or female gametes of L. purpureus.
-
23M.2.SL.TZ2.2a:
State how many chromosomes there would be in male or female gametes of L. purpureus.
-
23M.1.SL.TZ1.14:
Scientists sequenced the genes in each chromosome of chimpanzees (Pan troglodytes) and humans (Homo sapiens). The graph shows the mean divergence between the genes of these species by chromosome.
[Source: Material from: Mikkelsen, T.S. et al, Initial sequence of the chimpanzee genome and
comparison with the human genome, 2005 Nature, reproduced with permission of SNCSC.]
What can be deduced from this data?
A. Autosomes are more similar than Y chromosomes.B. There is the same number of chromosomes in humans and chimpanzees.
C. Humans are more closely related to chimpanzees than to other species.
D. Smaller chromosomes are more similar than larger chromosomes.
-
23M.1.HL.TZ1.10:
Scientists sequenced the genes in each chromosome of chimpanzees (Pan troglodytes) and humans (Homo sapiens). The graph shows the mean divergence between the genes of these species by chromosome.
[Source: Material from: Mikkelsen, T.S. et al, Initial sequence of the chimpanzee genome and
comparison with the human genome, 2005 Nature, reproduced with permission of SNCSC.]
What can be deduced from this data?
A. Autosomes are more similar than Y chromosomes.B. There is the same number of chromosomes in humans and chimpanzees.
C. Humans are more closely related to chimpanzees than to other species.
D. Smaller chromosomes are more similar than larger chromosomes.
-
23M.2.SL.TZ2.a:
State how many chromosomes there would be in male or female gametes of L. purpureus.
-
23M.2.SL.TZ1.6a:
Outline the sequence of events that occurs during mitosis.
-
23M.2.SL.TZ1.6a:
Outline the sequence of events that occurs during mitosis.
-
23M.2.SL.TZ1.a:
Outline the sequence of events that occurs during mitosis.