DP Chemistry (last assessment 2024)

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Question 19M.3.hl.TZ2.23

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Date May 2019 Marks available [Maximum mark: 4] Reference code 19M.3.hl.TZ2.23
Level hl Paper 3 Time zone TZ2
Command term Determine, Outline Question number 23 Adapted from N/A
23.
[Maximum mark: 4]
19M.3.hl.TZ2.23

Excess acid in the stomach can cause breakdown of the stomach lining.

(a(i))

Outline how ranitidine (Zantac) inhibits stomach acid production.

[1]

Markscheme

blocks/binds H2/histamine receptors «in cells of stomach lining»
OR
prevents histamine molecules binding to H2/histamine receptors «and triggering acid secretion»  [✔]

Examiners report

Some candidates were not confident enough in their answers to receive a mark while others confused the action of ranitidine which blocks H2 receptors with omeprazole which is a proton pump inhibitor.

(a(ii))

Outline two advantages of taking ranitidine instead of an antacid which neutralizes excess acid.

[2]

Markscheme

Any two of:
ranitidine can be effective in treating ulcers «but antacid is not»  [✔]
ranitidine can prevent long-term damage «from overproduction of acid and antacid does not» [✔]
ranitidine has a long-term effect «and antacid has short-term effect only» [✔]
ranitidine does not affect ionic balance in body «and antacid does» [✔]
ranitidine does not produce bloating/flatulence [✔]

 

Note: Accept “ranitidine stops the over production of acid in the stomach while antacids neutralise the excess acid
giving temporary relief” for M2.

Examiners report

While most candidates were awarded at least one of the two marks possible for this question some of the descriptions were too vague or incomplete to receive a mark.

(b)

Some antacids contain carbonates.

Determine the pH of a buffer solution which contains 0.160 mol dm−3 CO32− and 0.200 mol dm−3 HCO3, using section 1 of the data booklet.

pKa (HCO3) = 10.32

[1]

Markscheme

«pH = pKa  + log [ A ] [ HA] = 10.32 + log 0.160 0.200 = 10.32 0.097 »
«pH =»10.22   [✔]

Examiners report

This was generally a well-answered question. Most candidates who did not receive the mark inverted the concentration of the conjugate base/concentration of the acid in the calculation.