DP Chemistry (last assessment 2024)

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Question 20N.2.hl.TZ0.1b(iii)

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Date November 2020 Marks available [Maximum mark: 1] Reference code 20N.2.hl.TZ0.1b(iii)
Level hl Paper 2 Time zone TZ0
Command term Determine Question number b(iii) Adapted from N/A
b(iii).
[Maximum mark: 1]
20N.2.hl.TZ0.1b(iii)

Chlorine undergoes many reactions.

2.67g of manganese(IV) oxide was added to 200.0cm3 of 2.00moldm-3 HCl.

MnO2(s)+4HCl(aq)Cl2(g)+2H2O(l)+MnCl2(aq)

(b(iii))

Determine the excess amount, in mol, of the other reactant.

[1]

Markscheme

«0.0307mol×4=0.123mol»

«0.400mol0.123mol=»0.277«mol» ✔

Examiners report

Surprisingly, quite a number of candidates struggled with the quantity of excess reactant despite correctly identifying limiting reactant previously.