Directly related questions
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20N.2.sl.TZ0.1b(i):
Calculate the amount, in , of manganese(IV) oxide added.
-
20N.2.sl.TZ0.1b(i):
Calculate the amount, in , of manganese(IV) oxide added.
-
20N.2.sl.TZ0.b(i):
Calculate the amount, in , of manganese(IV) oxide added.
-
20N.2.hl.TZ0.1b(iii):
Determine the excess amount, in , of the other reactant.
-
20N.2.hl.TZ0.1b(iii):
Determine the excess amount, in , of the other reactant.
-
20N.2.hl.TZ0.b(iii):
Determine the excess amount, in , of the other reactant.
-
20N.2.hl.TZ0.1b(iv):
Calculate the volume of chlorine, in , produced if the reaction is conducted at standard temperature and pressure (STP). Use section 2 of the data booklet.
-
20N.2.hl.TZ0.1b(iv):
Calculate the volume of chlorine, in , produced if the reaction is conducted at standard temperature and pressure (STP). Use section 2 of the data booklet.
-
20N.2.hl.TZ0.b(iv):
Calculate the volume of chlorine, in , produced if the reaction is conducted at standard temperature and pressure (STP). Use section 2 of the data booklet.
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20N.3.hl.TZ0.11e(iii):
Suggest a wavenumber absorbed by methane gas.
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20N.3.hl.TZ0.11e(iii):
Suggest a wavenumber absorbed by methane gas.
-
20N.3.hl.TZ0.e(iii):
Suggest a wavenumber absorbed by methane gas.
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20N.3.hl.TZ0.12a:
Show that the mass of the 238U isotope in the rock is .
-
20N.3.hl.TZ0.12a:
Show that the mass of the 238U isotope in the rock is .
-
20N.3.hl.TZ0.a:
Show that the mass of the 238U isotope in the rock is .
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17N.2.hl.TZ0.2d.ii:
0.150 g sample of menthol, when vaporized, had a volume of 0.0337 dm3 at 150 °C and 100.2 kPa. Calculate its molar mass showing your working.
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17N.2.hl.TZ0.2d.ii:
0.150 g sample of menthol, when vaporized, had a volume of 0.0337 dm3 at 150 °C and 100.2 kPa. Calculate its molar mass showing your working.
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17N.2.hl.TZ0.d.ii:
0.150 g sample of menthol, when vaporized, had a volume of 0.0337 dm3 at 150 °C and 100.2 kPa. Calculate its molar mass showing your working.
-
17N.2.sl.TZ0.1c:
Calculate the concentration of ethanoic acid, CH3COOH, in mol dm–3.
-
17N.2.sl.TZ0.1c:
Calculate the concentration of ethanoic acid, CH3COOH, in mol dm–3.
-
17N.2.sl.TZ0.c:
Calculate the concentration of ethanoic acid, CH3COOH, in mol dm–3.
- 21M.1.sl.TZ2.2: Which amount, in mol, of sodium chloride is needed to make 250 cm3 of 0.10 mol dm−3...
- 21M.1.sl.TZ2.2: Which amount, in mol, of sodium chloride is needed to make 250 cm3 of 0.10 mol dm−3...
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21M.2.hl.TZ1.4c(ii):
8.00 g of methane is completely converted to methanol. Calculate, to three significant figures, the final volume of hydrogen at STP, in dm3. Use sections 2 and 6 of the data booklet.
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21M.2.hl.TZ1.4c(ii):
8.00 g of methane is completely converted to methanol. Calculate, to three significant figures, the final volume of hydrogen at STP, in dm3. Use sections 2 and 6 of the data booklet.
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21M.2.hl.TZ1.c(ii):
8.00 g of methane is completely converted to methanol. Calculate, to three significant figures, the final volume of hydrogen at STP, in dm3. Use sections 2 and 6 of the data booklet.
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21M.2.sl.TZ2.1d(ii):
Determine the volume, in dm3, of 0.015 mol dm−3 calcium hydroxide solution needed to neutralize 35.0 cm3 of 0.025 mol dm−3 HCl (aq).
-
21M.2.sl.TZ2.d(ii):
Determine the volume, in dm3, of 0.015 mol dm−3 calcium hydroxide solution needed to neutralize 35.0 cm3 of 0.025 mol dm−3 HCl (aq).
-
21M.2.sl.TZ2.1d(ii):
Determine the volume, in dm3, of 0.015 mol dm−3 calcium hydroxide solution needed to neutralize 35.0 cm3 of 0.025 mol dm−3 HCl (aq).
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21M.2.hl.TZ2.1d(ii):
2.85 g of CaCO3 was collected in the experiment in d(i). Calculate the percentage yield of CaCO3.
(If you did not obtain an answer to d(i), use 4.00 g, but this is not the correct value.)
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21M.2.hl.TZ2.1d(ii):
2.85 g of CaCO3 was collected in the experiment in d(i). Calculate the percentage yield of CaCO3.
(If you did not obtain an answer to d(i), use 4.00 g, but this is not the correct value.)
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21M.2.hl.TZ2.d(ii):
2.85 g of CaCO3 was collected in the experiment in d(i). Calculate the percentage yield of CaCO3.
(If you did not obtain an answer to d(i), use 4.00 g, but this is not the correct value.)
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18M.2.hl.TZ1.1g:
Calculate the maximum volume of CO2, in cm3, produced at STP by the combustion of 0.600 g of urea, using sections 2 and 6 of the data booklet.
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18M.2.hl.TZ1.1g:
Calculate the maximum volume of CO2, in cm3, produced at STP by the combustion of 0.600 g of urea, using sections 2 and 6 of the data booklet.
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18M.2.hl.TZ1.g:
Calculate the maximum volume of CO2, in cm3, produced at STP by the combustion of 0.600 g of urea, using sections 2 and 6 of the data booklet.
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18M.2.hl.TZ1.1c:
Urea can be made by reacting potassium cyanate, KNCO, with ammonium chloride, NH4Cl.
KNCO(aq) + NH4Cl(aq) → (H2N)2CO(aq) + KCl(aq)
Determine the maximum mass of urea that could be formed from 50.0 cm3 of 0.100 mol dm−3 potassium cyanate solution.
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18M.2.hl.TZ1.1c:
Urea can be made by reacting potassium cyanate, KNCO, with ammonium chloride, NH4Cl.
KNCO(aq) + NH4Cl(aq) → (H2N)2CO(aq) + KCl(aq)
Determine the maximum mass of urea that could be formed from 50.0 cm3 of 0.100 mol dm−3 potassium cyanate solution.
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18M.2.hl.TZ1.c:
Urea can be made by reacting potassium cyanate, KNCO, with ammonium chloride, NH4Cl.
KNCO(aq) + NH4Cl(aq) → (H2N)2CO(aq) + KCl(aq)
Determine the maximum mass of urea that could be formed from 50.0 cm3 of 0.100 mol dm−3 potassium cyanate solution.
- 18M.1.sl.TZ1.3: Which graph shows the relationship between the volume and pressure of a fixed mass of an ideal...
- 18M.1.sl.TZ1.3: Which graph shows the relationship between the volume and pressure of a fixed mass of an ideal...
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18M.1.sl.TZ1.4:
What is the percentage yield when 7 g of ethene produces 6 g of ethanol?
Mr(ethene) = 28 and Mr(ethanol) = 46
C2H4(g) + H2O(g) → C2H5OH(g)
A.
B.
C.
D.
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18M.1.sl.TZ1.4:
What is the percentage yield when 7 g of ethene produces 6 g of ethanol?
Mr(ethene) = 28 and Mr(ethanol) = 46
C2H4(g) + H2O(g) → C2H5OH(g)
A.
B.
C.
D.
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18M.1.sl.TZ2.3:
What is the volume, in cm3, of the final solution if 100 cm3 of a solution containing 1.42 g of sodium sulfate, Na2SO4, is diluted to the concentration of 0.020 mol dm–3?
Mr(Na2SO4) = 142
A. 50
B. 400
C. 500
D. 600
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18M.1.sl.TZ2.3:
What is the volume, in cm3, of the final solution if 100 cm3 of a solution containing 1.42 g of sodium sulfate, Na2SO4, is diluted to the concentration of 0.020 mol dm–3?
Mr(Na2SO4) = 142
A. 50
B. 400
C. 500
D. 600
- 18M.1.sl.TZ2.6: Which electron transition emits energy of the longest wavelength?
- 18M.1.sl.TZ2.6: Which electron transition emits energy of the longest wavelength?
- 21N.1.sl.TZ0.4: The two containers shown are connected by a valve. What is the total pressure after the valve is...
- 21N.1.sl.TZ0.4: The two containers shown are connected by a valve. What is the total pressure after the valve is...
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21N.2.sl.TZ0.6c(i):
Calculate the amount, in moles of Na2S2O3 used in the titration.
-
21N.2.sl.TZ0.6c(i):
Calculate the amount, in moles of Na2S2O3 used in the titration.
-
21N.2.sl.TZ0.c(i):
Calculate the amount, in moles of Na2S2O3 used in the titration.
- 21N.2.sl.TZ0.6c(ii): Deduce the mole ratio of O2 consumed in step I to S2O32− used in step III.
- 21N.2.sl.TZ0.6c(ii): Deduce the mole ratio of O2 consumed in step I to S2O32− used in step III.
- 21N.2.sl.TZ0.c(ii): Deduce the mole ratio of O2 consumed in step I to S2O32− used in step III.
-
21N.2.sl.TZ0.6c(iii):
Calculate the concentration of dissolved oxygen, in mol dm−3, in the sample.
-
21N.2.sl.TZ0.6c(iii):
Calculate the concentration of dissolved oxygen, in mol dm−3, in the sample.
-
21N.2.sl.TZ0.c(iii):
Calculate the concentration of dissolved oxygen, in mol dm−3, in the sample.
- 21N.2.hl.TZ0.6c(ii): Deduce the mole ratio of O2 consumed in step I to S2O32− used in step III.
- 21N.2.hl.TZ0.c(ii): Deduce the mole ratio of O2 consumed in step I to S2O32− used in step III.
- 21N.2.hl.TZ0.6c(ii): Deduce the mole ratio of O2 consumed in step I to S2O32− used in step III.
-
21N.2.hl.TZ0.5c:
Calculate the concentration of H3PO4 if 25.00 cm3 is completely neutralised by the addition of 28.40 cm3 of 0.5000 mol dm−3 NaOH.
-
21N.2.hl.TZ0.5c:
Calculate the concentration of H3PO4 if 25.00 cm3 is completely neutralised by the addition of 28.40 cm3 of 0.5000 mol dm−3 NaOH.
-
21N.2.hl.TZ0.c:
Calculate the concentration of H3PO4 if 25.00 cm3 is completely neutralised by the addition of 28.40 cm3 of 0.5000 mol dm−3 NaOH.
-
21N.2.hl.TZ0.6c(i):
Calculate the amount, in moles of Na2S2O3 used in the titration.
-
21N.2.hl.TZ0.c(i):
Calculate the amount, in moles of Na2S2O3 used in the titration.
-
21N.2.hl.TZ0.6c(i):
Calculate the amount, in moles of Na2S2O3 used in the titration.
-
21N.2.hl.TZ0.6c(iii):
Calculate the concentration of dissolved oxygen, in mol dm−3, in the sample.
-
21N.2.hl.TZ0.c(iii):
Calculate the concentration of dissolved oxygen, in mol dm−3, in the sample.
-
21N.2.hl.TZ0.6c(iii):
Calculate the concentration of dissolved oxygen, in mol dm−3, in the sample.
-
22M.1.sl.TZ1.2:
Which sample contains the fewest moles of HCl?
NA = 6.02 × 1023 mol–1.
Molar volume of an ideal gas at STP = 22.7 dm3 mol–1.
A. 10.0 cm3 of 0.1 mol dm–3 HCl (aq)B. 6.02 × 1024 molecules of HCl (g)
C. 0.365 g of HCl (g)
D. 2.27 dm3 of HCl (g) at STP
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22M.1.sl.TZ1.2:
Which sample contains the fewest moles of HCl?
NA = 6.02 × 1023 mol–1.
Molar volume of an ideal gas at STP = 22.7 dm3 mol–1.
A. 10.0 cm3 of 0.1 mol dm–3 HCl (aq)B. 6.02 × 1024 molecules of HCl (g)
C. 0.365 g of HCl (g)
D. 2.27 dm3 of HCl (g) at STP
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18N.3.sl.TZ0.1f.ii:
Suggest why the end point of the titration is difficult to determine, even with the addition of starch to turn the remaining free iodine black.
-
18N.3.sl.TZ0.1f.ii:
Suggest why the end point of the titration is difficult to determine, even with the addition of starch to turn the remaining free iodine black.
-
18N.3.sl.TZ0.f.ii:
Suggest why the end point of the titration is difficult to determine, even with the addition of starch to turn the remaining free iodine black.
-
18N.2.sl.TZ0.1a.i:
Determine the limiting reactant showing your working.
-
18N.2.sl.TZ0.1a.i:
Determine the limiting reactant showing your working.
-
18N.2.sl.TZ0.a.i:
Determine the limiting reactant showing your working.
-
18N.3.sl.TZ0.1c:
Outline how a solution of 0.0100 mol dm−3 is obtained from a standard 1.000 mol dm−3 copper(II) sulfate solution, including two essential pieces of glassware you would need.
-
18N.3.sl.TZ0.1c:
Outline how a solution of 0.0100 mol dm−3 is obtained from a standard 1.000 mol dm−3 copper(II) sulfate solution, including two essential pieces of glassware you would need.
-
18N.3.sl.TZ0.c:
Outline how a solution of 0.0100 mol dm−3 is obtained from a standard 1.000 mol dm−3 copper(II) sulfate solution, including two essential pieces of glassware you would need.
-
18N.3.hl.TZ0.1g:
Titration is another method for analysing the solution obtained from adding brass to nitric acid.
Copper(II) ions are reduced to copper(I) iodide by the addition of potassium iodide solution, releasing iodine that can be titrated with sodium thiosulfate solution, Na2S2O3 (aq). Copper(I) iodide is a white solid.
4I− (aq) + 2Cu2+ (aq) → 2CuI (s) + I2 (aq)
I2 (aq) + 2S2O32− (aq) → 2I− (aq) + S4O62− (aq)
Suggest why the end point of the titration is difficult to determine, even with the addition of starch to turn the remaining free iodine black.
-
18N.3.hl.TZ0.1g:
Titration is another method for analysing the solution obtained from adding brass to nitric acid.
Copper(II) ions are reduced to copper(I) iodide by the addition of potassium iodide solution, releasing iodine that can be titrated with sodium thiosulfate solution, Na2S2O3 (aq). Copper(I) iodide is a white solid.
4I− (aq) + 2Cu2+ (aq) → 2CuI (s) + I2 (aq)
I2 (aq) + 2S2O32− (aq) → 2I− (aq) + S4O62− (aq)
Suggest why the end point of the titration is difficult to determine, even with the addition of starch to turn the remaining free iodine black.
-
18N.3.hl.TZ0.g:
Titration is another method for analysing the solution obtained from adding brass to nitric acid.
Copper(II) ions are reduced to copper(I) iodide by the addition of potassium iodide solution, releasing iodine that can be titrated with sodium thiosulfate solution, Na2S2O3 (aq). Copper(I) iodide is a white solid.
4I− (aq) + 2Cu2+ (aq) → 2CuI (s) + I2 (aq)
I2 (aq) + 2S2O32− (aq) → 2I− (aq) + S4O62− (aq)
Suggest why the end point of the titration is difficult to determine, even with the addition of starch to turn the remaining free iodine black.
-
18N.3.hl.TZ0.1d:
Outline how a solution of 0.0100 mol dm−3 is obtained from a standard 1.000 mol dm−3 copper(II) sulfate solution, including two essential pieces of glassware you would need.
-
18N.3.hl.TZ0.1d:
Outline how a solution of 0.0100 mol dm−3 is obtained from a standard 1.000 mol dm−3 copper(II) sulfate solution, including two essential pieces of glassware you would need.
-
18N.3.hl.TZ0.d:
Outline how a solution of 0.0100 mol dm−3 is obtained from a standard 1.000 mol dm−3 copper(II) sulfate solution, including two essential pieces of glassware you would need.
- 22M.1.sl.TZ2.1: What is the concentration of chloride ions, in mol dm−3, in a solution formed by mixing 200 cm3...
- 22M.1.sl.TZ2.1: What is the concentration of chloride ions, in mol dm−3, in a solution formed by mixing 200 cm3...
-
22M.2.sl.TZ1.1c(i):
Evaluate whether this, rather than the loss of product, could explain the yield found in (b)(iii).
-
22M.2.sl.TZ1.1c(i):
Evaluate whether this, rather than the loss of product, could explain the yield found in (b)(iii).
-
22M.2.sl.TZ1.c(i):
Evaluate whether this, rather than the loss of product, could explain the yield found in (b)(iii).
-
19M.2.hl.TZ2.5d(iii):
100.0cm3 of soda water contains 3.0 × 10−2g NaHCO3.
Calculate the concentration of NaHCO3 in mol dm−3.
-
19M.2.hl.TZ2.5d(iii):
100.0cm3 of soda water contains 3.0 × 10−2g NaHCO3.
Calculate the concentration of NaHCO3 in mol dm−3.
-
19M.2.hl.TZ2.d(iii):
100.0cm3 of soda water contains 3.0 × 10−2g NaHCO3.
Calculate the concentration of NaHCO3 in mol dm−3.
-
19M.3.hl.TZ2.1c(ii):
A mean daily lead intake of greater than 5.0 × 10−6 g per kg of body weight results in increased lead levels in the body.
Calculate the volume, in dm3, of tap water from experiment 8 which would exceed this daily lead intake for an 80.0 kg man.
-
19M.3.hl.TZ2.1c(ii):
A mean daily lead intake of greater than 5.0 × 10−6 g per kg of body weight results in increased lead levels in the body.
Calculate the volume, in dm3, of tap water from experiment 8 which would exceed this daily lead intake for an 80.0 kg man.
-
19M.3.hl.TZ2.c(ii):
A mean daily lead intake of greater than 5.0 × 10−6 g per kg of body weight results in increased lead levels in the body.
Calculate the volume, in dm3, of tap water from experiment 8 which would exceed this daily lead intake for an 80.0 kg man.
- 19M.1.hl.TZ2.3: What is the volume of gas when the pressure on 100 cm3 of gas is changed from 400 kPa to 200 kPa...
- 19M.1.hl.TZ2.3: What is the volume of gas when the pressure on 100 cm3 of gas is changed from 400 kPa to 200 kPa...
-
19M.1.sl.TZ2.4:
What is the concentration, in mol dm−3, of 20.0 g of NaOH (Mr = 40.0) in 500.0 cm3?
A. 0.250
B. 0.500
C. 1.00
D. 4.00
-
19M.1.sl.TZ2.4:
What is the concentration, in mol dm−3, of 20.0 g of NaOH (Mr = 40.0) in 500.0 cm3?
A. 0.250
B. 0.500
C. 1.00
D. 4.00
-
19N.2.sl.TZ0.6a(iii):
Calculate the pressure, in kPa, of this gas in a 10.0 dm3 air bag at 127°C, assuming no gas escapes.
-
19N.2.sl.TZ0.6a(iii):
Calculate the pressure, in kPa, of this gas in a 10.0 dm3 air bag at 127°C, assuming no gas escapes.
-
19N.2.sl.TZ0.a(iii):
Calculate the pressure, in kPa, of this gas in a 10.0 dm3 air bag at 127°C, assuming no gas escapes.
-
19N.1.sl.TZ0.1:
0.10 mol of hydrochloric acid is mixed with 0.10 mol of calcium carbonate.
2HCl (aq) + CaCO3 (s) → CaCl2 (aq) + H2O (l) + CO2 (g)
Which is correct?
-
19N.1.sl.TZ0.1:
0.10 mol of hydrochloric acid is mixed with 0.10 mol of calcium carbonate.
2HCl (aq) + CaCO3 (s) → CaCl2 (aq) + H2O (l) + CO2 (g)
Which is correct?
-
19N.2.hl.TZ0.6b:
Solid copper(II) chloride absorbs moisture from the atmosphere to form a hydrate of formula CuCl2•H2O.
A student heated a sample of hydrated copper(II) chloride, in order to determine the value of . The following results were obtained:
Mass of crucible = 16.221 g
Initial mass of crucible and hydrated copper(II) chloride = 18.360 g
Final mass of crucible and anhydrous copper(II) chloride = 17.917 gDetermine the value of .
-
19N.2.hl.TZ0.6b:
Solid copper(II) chloride absorbs moisture from the atmosphere to form a hydrate of formula CuCl2•H2O.
A student heated a sample of hydrated copper(II) chloride, in order to determine the value of . The following results were obtained:
Mass of crucible = 16.221 g
Initial mass of crucible and hydrated copper(II) chloride = 18.360 g
Final mass of crucible and anhydrous copper(II) chloride = 17.917 gDetermine the value of .
-
19N.2.hl.TZ0.b:
Solid copper(II) chloride absorbs moisture from the atmosphere to form a hydrate of formula CuCl2•H2O.
A student heated a sample of hydrated copper(II) chloride, in order to determine the value of . The following results were obtained:
Mass of crucible = 16.221 g
Initial mass of crucible and hydrated copper(II) chloride = 18.360 g
Final mass of crucible and anhydrous copper(II) chloride = 17.917 gDetermine the value of .
- 19N.3.sl.TZ0.2a(i): Describe the effect of increasing the voltage on the chemical yield of: Ethanal using...
- 19N.3.sl.TZ0.2a(i): Describe the effect of increasing the voltage on the chemical yield of: Ethanal using...
- 19N.3.sl.TZ0.a(i): Describe the effect of increasing the voltage on the chemical yield of: Ethanal using...
-
19N.2.sl.TZ0.5b:
Solid copper(II) chloride absorbs moisture from the atmosphere to form a hydrate of formula CuCl2•H2O.
A student heated a sample of hydrated copper(II) chloride, in order to determine the value of . The following results were obtained:
Mass of crucible = 16.221 g
Initial mass of crucible and hydrated copper(II) chloride = 18.360 g
Final mass of crucible and anhydrous copper(II) chloride = 17.917 gDetermine the value of .
-
19N.2.sl.TZ0.5b:
Solid copper(II) chloride absorbs moisture from the atmosphere to form a hydrate of formula CuCl2•H2O.
A student heated a sample of hydrated copper(II) chloride, in order to determine the value of . The following results were obtained:
Mass of crucible = 16.221 g
Initial mass of crucible and hydrated copper(II) chloride = 18.360 g
Final mass of crucible and anhydrous copper(II) chloride = 17.917 gDetermine the value of .
-
19N.2.sl.TZ0.b:
Solid copper(II) chloride absorbs moisture from the atmosphere to form a hydrate of formula CuCl2•H2O.
A student heated a sample of hydrated copper(II) chloride, in order to determine the value of . The following results were obtained:
Mass of crucible = 16.221 g
Initial mass of crucible and hydrated copper(II) chloride = 18.360 g
Final mass of crucible and anhydrous copper(II) chloride = 17.917 gDetermine the value of .
-
22N.2.sl.TZ0.1f.ii:
Calculate the volume of dinitrogen monoxide produced at STP when a 5.00 g sample of ammonium nitrate decomposes. Use section 2 of the data booklet.
-
22N.2.sl.TZ0.1f.ii:
Calculate the volume of dinitrogen monoxide produced at STP when a 5.00 g sample of ammonium nitrate decomposes. Use section 2 of the data booklet.
-
22N.2.sl.TZ0.f.ii:
Calculate the volume of dinitrogen monoxide produced at STP when a 5.00 g sample of ammonium nitrate decomposes. Use section 2 of the data booklet.
-
22N.2.hl.TZ0.1f.ii:
Calculate the volume of dinitrogen monoxide produced at STP when a 5.00 g sample of ammonium nitrate decomposes. Use section 2 of the data booklet.
-
22N.2.hl.TZ0.1f.ii:
Calculate the volume of dinitrogen monoxide produced at STP when a 5.00 g sample of ammonium nitrate decomposes. Use section 2 of the data booklet.
-
22N.2.hl.TZ0.f.ii:
Calculate the volume of dinitrogen monoxide produced at STP when a 5.00 g sample of ammonium nitrate decomposes. Use section 2 of the data booklet.
-
22N.2.hl.TZ0.5a:
Calculate the amount, in mol, of sulfur dioxide produced when 500.0 g of lignite undergoes combustion.
S (s) + O2 (g) → SO2 (g)
-
22N.2.hl.TZ0.5a:
Calculate the amount, in mol, of sulfur dioxide produced when 500.0 g of lignite undergoes combustion.
S (s) + O2 (g) → SO2 (g)
-
22N.2.hl.TZ0.a:
Calculate the amount, in mol, of sulfur dioxide produced when 500.0 g of lignite undergoes combustion.
S (s) + O2 (g) → SO2 (g)
-
17N.1.hl.TZ0.3:
What is the pressure, in Pa, inside a 1.0 m3 cylinder containing 10 kg of H2 (g) at 25 ºC?
R = 8.31 J K–1 mol–1; pV = nRT
A.
B.
C.
D.
-
17N.1.hl.TZ0.3:
What is the pressure, in Pa, inside a 1.0 m3 cylinder containing 10 kg of H2 (g) at 25 ºC?
R = 8.31 J K–1 mol–1; pV = nRT
A.
B.
C.
D.
-
17N.2.sl.TZ0.4b:
0.150 g sample of menthol, when vaporized, had a volume of 0.0337 dm3 at 150 °C and 100.2 kPa. Calculate its molar mass showing your working.
-
17N.2.sl.TZ0.4b:
0.150 g sample of menthol, when vaporized, had a volume of 0.0337 dm3 at 150 °C and 100.2 kPa. Calculate its molar mass showing your working.
-
17N.2.sl.TZ0.b:
0.150 g sample of menthol, when vaporized, had a volume of 0.0337 dm3 at 150 °C and 100.2 kPa. Calculate its molar mass showing your working.
-
18M.2.sl.TZ1.1c:
Urea can be made by reacting potassium cyanate, KNCO, with ammonium chloride, NH4Cl.
KNCO(aq) + NH4Cl(aq) → (H2N)2CO(aq) + KCl(aq)
Determine the maximum mass of urea that could be formed from 50.0 cm3 of 0.100 mol dm−3 potassium cyanate solution.
-
18M.2.sl.TZ1.1c:
Urea can be made by reacting potassium cyanate, KNCO, with ammonium chloride, NH4Cl.
KNCO(aq) + NH4Cl(aq) → (H2N)2CO(aq) + KCl(aq)
Determine the maximum mass of urea that could be formed from 50.0 cm3 of 0.100 mol dm−3 potassium cyanate solution.
-
18M.2.sl.TZ1.c:
Urea can be made by reacting potassium cyanate, KNCO, with ammonium chloride, NH4Cl.
KNCO(aq) + NH4Cl(aq) → (H2N)2CO(aq) + KCl(aq)
Determine the maximum mass of urea that could be formed from 50.0 cm3 of 0.100 mol dm−3 potassium cyanate solution.
-
18M.1.sl.TZ2.4:
What is the percentage yield when 2.0 g of ethene, C2H4, is formed from 5.0 g of ethanol, C2H5OH?
Mr(ethene) = 28; Mr(ethanol) = 46A.
B.
C.
D.
-
18M.1.sl.TZ2.4:
What is the percentage yield when 2.0 g of ethene, C2H4, is formed from 5.0 g of ethanol, C2H5OH?
Mr(ethene) = 28; Mr(ethanol) = 46A.
B.
C.
D.
-
18M.2.sl.TZ2.1a:
Calculate the amount, in mol, of H2SO4.
-
18M.2.sl.TZ2.1a:
Calculate the amount, in mol, of H2SO4.
-
18M.2.sl.TZ2.a:
Calculate the amount, in mol, of H2SO4.
-
18M.2.sl.TZ2.1c:
The excess sulfuric acid required 20.80 cm3 of 0.1133 mol dm−3 NaOH for neutralization.
Calculate the amount of excess acid present.
-
18M.2.sl.TZ2.1c:
The excess sulfuric acid required 20.80 cm3 of 0.1133 mol dm−3 NaOH for neutralization.
Calculate the amount of excess acid present.
-
18M.2.sl.TZ2.c:
The excess sulfuric acid required 20.80 cm3 of 0.1133 mol dm−3 NaOH for neutralization.
Calculate the amount of excess acid present.
-
18M.2.sl.TZ2.1d:
Calculate the amount of H2SO4 that reacted with Mg(OH)2.
-
18M.2.sl.TZ2.1d:
Calculate the amount of H2SO4 that reacted with Mg(OH)2.
-
18M.2.sl.TZ2.d:
Calculate the amount of H2SO4 that reacted with Mg(OH)2.
-
18M.2.sl.TZ2.1f:
Calculate the percentage by mass of magnesium hydroxide in the 1.24 g antacid tablet to three significant figures.
-
18M.2.sl.TZ2.1f:
Calculate the percentage by mass of magnesium hydroxide in the 1.24 g antacid tablet to three significant figures.
-
18M.2.sl.TZ2.f:
Calculate the percentage by mass of magnesium hydroxide in the 1.24 g antacid tablet to three significant figures.
- 18N.1.sl.TZ0.2: The volume of a sample of gas measured at 27 °C is 10.0 dm3. What is the temperature when the...
- 18N.1.sl.TZ0.2: The volume of a sample of gas measured at 27 °C is 10.0 dm3. What is the temperature when the...
-
18N.1.sl.TZ0.4:
An antacid tablet containing 0.50 g of NaHCO3 (Mr = 84) is dissolved in water to give a volume of 250 cm3. What is the concentration, in mol dm−3, of HCO3− in this solution?
A.
B.
C.
D.
-
18N.1.sl.TZ0.4:
An antacid tablet containing 0.50 g of NaHCO3 (Mr = 84) is dissolved in water to give a volume of 250 cm3. What is the concentration, in mol dm−3, of HCO3− in this solution?
A.
B.
C.
D.
-
18N.2.sl.TZ0.1a.ii:
The mass of copper obtained experimentally was 0.872 g. Calculate the percentage yield of copper.
-
18N.2.sl.TZ0.1a.ii:
The mass of copper obtained experimentally was 0.872 g. Calculate the percentage yield of copper.
-
18N.2.sl.TZ0.a.ii:
The mass of copper obtained experimentally was 0.872 g. Calculate the percentage yield of copper.
-
18N.2.hl.TZ0.1a.i:
Determine the limiting reactant showing your working.
-
18N.2.hl.TZ0.1a.i:
Determine the limiting reactant showing your working.
-
18N.2.hl.TZ0.a.i:
Determine the limiting reactant showing your working.
-
18N.2.hl.TZ0.1a.ii:
The mass of copper obtained experimentally was 0.872 g. Calculate the percentage yield of copper.
-
18N.2.hl.TZ0.1a.ii:
The mass of copper obtained experimentally was 0.872 g. Calculate the percentage yield of copper.
-
18N.2.hl.TZ0.a.ii:
The mass of copper obtained experimentally was 0.872 g. Calculate the percentage yield of copper.
-
18N.3.sl.TZ0.1f.i:
Copper(II) ions are reduced to copper(I) iodide by the addition of potassium iodide solution, releasing iodine that can be titrated with sodium thiosulfate solution, Na2S2O3 (aq). Copper(I) iodide is a white solid.
4I− (aq) + 2Cu2+ (aq) → 2CuI (s) + I2 (aq)
I2 (aq) + 2S2O32− (aq) → 2I− (aq) + S4O62− (aq)
Deduce the overall equation for the two reactions by combining the two equations.
-
18N.3.sl.TZ0.1f.i:
Copper(II) ions are reduced to copper(I) iodide by the addition of potassium iodide solution, releasing iodine that can be titrated with sodium thiosulfate solution, Na2S2O3 (aq). Copper(I) iodide is a white solid.
4I− (aq) + 2Cu2+ (aq) → 2CuI (s) + I2 (aq)
I2 (aq) + 2S2O32− (aq) → 2I− (aq) + S4O62− (aq)
Deduce the overall equation for the two reactions by combining the two equations.
-
18N.3.sl.TZ0.f.i:
Copper(II) ions are reduced to copper(I) iodide by the addition of potassium iodide solution, releasing iodine that can be titrated with sodium thiosulfate solution, Na2S2O3 (aq). Copper(I) iodide is a white solid.
4I− (aq) + 2Cu2+ (aq) → 2CuI (s) + I2 (aq)
I2 (aq) + 2S2O32− (aq) → 2I− (aq) + S4O62− (aq)
Deduce the overall equation for the two reactions by combining the two equations.
-
19M.2.hl.TZ1.3f:
Sodium peroxide, Na2O2, is formed by the reaction of sodium oxide with oxygen.
2Na2O (s) + O2 (g) → 2Na2O2 (s)
Calculate the percentage yield of sodium peroxide if 5.00g of sodium oxide produces 5.50g of sodium peroxide.
-
19M.2.hl.TZ1.3f:
Sodium peroxide, Na2O2, is formed by the reaction of sodium oxide with oxygen.
2Na2O (s) + O2 (g) → 2Na2O2 (s)
Calculate the percentage yield of sodium peroxide if 5.00g of sodium oxide produces 5.50g of sodium peroxide.
-
19M.2.hl.TZ1.f:
Sodium peroxide, Na2O2, is formed by the reaction of sodium oxide with oxygen.
2Na2O (s) + O2 (g) → 2Na2O2 (s)
Calculate the percentage yield of sodium peroxide if 5.00g of sodium oxide produces 5.50g of sodium peroxide.
-
19M.2.hl.TZ1.3i:
Outline why a real gas differs from ideal behaviour at low temperature and high pressure.
-
19M.2.hl.TZ1.3i:
Outline why a real gas differs from ideal behaviour at low temperature and high pressure.
-
19M.2.hl.TZ1.i:
Outline why a real gas differs from ideal behaviour at low temperature and high pressure.
-
19M.2.hl.TZ2.2a:
Explain why, as the reaction proceeds, the pressure increases by the amount shown.
-
19M.2.hl.TZ2.2a:
Explain why, as the reaction proceeds, the pressure increases by the amount shown.
-
19M.2.hl.TZ2.a:
Explain why, as the reaction proceeds, the pressure increases by the amount shown.
-
19M.2.hl.TZ2.2d:
The experiment is repeated using the same amount of dinitrogen monoxide in the same apparatus, but at a lower temperature.
Sketch, on the axes in question 2, the graph that you would expect.
-
19M.2.hl.TZ2.2d:
The experiment is repeated using the same amount of dinitrogen monoxide in the same apparatus, but at a lower temperature.
Sketch, on the axes in question 2, the graph that you would expect.
-
19M.2.hl.TZ2.d:
The experiment is repeated using the same amount of dinitrogen monoxide in the same apparatus, but at a lower temperature.
Sketch, on the axes in question 2, the graph that you would expect.
-
19M.1.hl.TZ1.2:
What volume of carbon dioxide, CO2 (g), can be obtained by reacting 1 dm3 of methane, CH4 (g), with 1 dm3 of oxygen, O2 (g)?
CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (l)
A. 0.5 dm3
B. 1 dm3
C. 2 dm3
D. 6 dm3
-
19M.1.hl.TZ1.2:
What volume of carbon dioxide, CO2 (g), can be obtained by reacting 1 dm3 of methane, CH4 (g), with 1 dm3 of oxygen, O2 (g)?
CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (l)
A. 0.5 dm3
B. 1 dm3
C. 2 dm3
D. 6 dm3
-
19M.2.sl.TZ1.3b:
Sodium peroxide, Na2O2, is formed by the reaction of sodium oxide with oxygen.
2Na2O (s) + O2 (g) → 2Na2O2 (s)
Calculate the percentage yield of sodium peroxide if 5.00 g of sodium oxide produces 5.50 g of sodium peroxide.
-
19M.2.sl.TZ1.3b:
Sodium peroxide, Na2O2, is formed by the reaction of sodium oxide with oxygen.
2Na2O (s) + O2 (g) → 2Na2O2 (s)
Calculate the percentage yield of sodium peroxide if 5.00 g of sodium oxide produces 5.50 g of sodium peroxide.
-
19M.2.sl.TZ1.b:
Sodium peroxide, Na2O2, is formed by the reaction of sodium oxide with oxygen.
2Na2O (s) + O2 (g) → 2Na2O2 (s)
Calculate the percentage yield of sodium peroxide if 5.00 g of sodium oxide produces 5.50 g of sodium peroxide.
-
19M.2.sl.TZ2.2a:
Explain why, as the reaction proceeds, the pressure increases by the amount shown.
-
19M.2.sl.TZ2.2a:
Explain why, as the reaction proceeds, the pressure increases by the amount shown.
-
19M.2.sl.TZ2.a:
Explain why, as the reaction proceeds, the pressure increases by the amount shown.
-
19M.2.sl.TZ2.2c:
The experiment is repeated using the same amount of dinitrogen monoxide in the same apparatus, but at a lower temperature.
Sketch, on the axes in question 2, the graph that you would expect.
-
19M.2.sl.TZ2.2c:
The experiment is repeated using the same amount of dinitrogen monoxide in the same apparatus, but at a lower temperature.
Sketch, on the axes in question 2, the graph that you would expect.
-
19M.2.sl.TZ2.c:
The experiment is repeated using the same amount of dinitrogen monoxide in the same apparatus, but at a lower temperature.
Sketch, on the axes in question 2, the graph that you would expect.
-
19M.2.sl.TZ2.5b(ii):
100.0 cm3 of soda water contains 3.0 × 10−2 g NaHCO3.
Calculate the concentration of NaHCO3 in mol dm−3.
-
19M.2.sl.TZ2.5b(ii):
100.0 cm3 of soda water contains 3.0 × 10−2 g NaHCO3.
Calculate the concentration of NaHCO3 in mol dm−3.
-
19M.2.sl.TZ2.b(ii):
100.0 cm3 of soda water contains 3.0 × 10−2 g NaHCO3.
Calculate the concentration of NaHCO3 in mol dm−3.
-
19M.3.sl.TZ2.1c(ii):
A mean daily lead intake of greater than 5.0 × 10−6 g per kg of body weight results in increased lead levels in the body.
Calculate the volume, in dm3, of tap water from experiment 8 which would exceed this daily lead intake for an 80.0 kg man.
-
19M.3.sl.TZ2.1c(ii):
A mean daily lead intake of greater than 5.0 × 10−6 g per kg of body weight results in increased lead levels in the body.
Calculate the volume, in dm3, of tap water from experiment 8 which would exceed this daily lead intake for an 80.0 kg man.
-
19M.3.sl.TZ2.c(ii):
A mean daily lead intake of greater than 5.0 × 10−6 g per kg of body weight results in increased lead levels in the body.
Calculate the volume, in dm3, of tap water from experiment 8 which would exceed this daily lead intake for an 80.0 kg man.
-
19M.1.sl.TZ1.4:
Which graph would not show a linear relationship for a fixed mass of an ideal gas with all other variables constant?
A. P against V
B. P against
C. P against T
D. V against T
-
19M.1.sl.TZ1.4:
Which graph would not show a linear relationship for a fixed mass of an ideal gas with all other variables constant?
A. P against V
B. P against
C. P against T
D. V against T
-
19M.1.sl.TZ2.3:
What is the volume of gas when the pressure on 100 cm3 of gas is changed from 400 kPa to 200 kPa at constant temperature?
A. 50.0 cm3
B. 100 cm3
C. 200 cm3
D. 800 cm3
-
19M.1.sl.TZ2.3:
What is the volume of gas when the pressure on 100 cm3 of gas is changed from 400 kPa to 200 kPa at constant temperature?
A. 50.0 cm3
B. 100 cm3
C. 200 cm3
D. 800 cm3
- 19N.2.sl.TZ0.2a(i): Determine the mole ratio of S2O32− to O2, using the balanced equations.
- 19N.2.sl.TZ0.2a(i): Determine the mole ratio of S2O32− to O2, using the balanced equations.
- 19N.2.sl.TZ0.a(i): Determine the mole ratio of S2O32− to O2, using the balanced equations.
-
19N.2.sl.TZ0.2a(iii):
The day 5 sample contained 5.03 × 10−5 moles of oxygen.
Determine the 5-day biochemical oxygen demand of the pond, in mg dm−3 (“parts per million”, ppm).
-
19N.2.sl.TZ0.2a(iii):
The day 5 sample contained 5.03 × 10−5 moles of oxygen.
Determine the 5-day biochemical oxygen demand of the pond, in mg dm−3 (“parts per million”, ppm).
-
19N.2.sl.TZ0.a(iii):
The day 5 sample contained 5.03 × 10−5 moles of oxygen.
Determine the 5-day biochemical oxygen demand of the pond, in mg dm−3 (“parts per million”, ppm).
- 19N.2.sl.TZ0.6a(iv): Suggest why water vapour deviates significantly from ideal behaviour when the gases are cooled,...
- 19N.2.sl.TZ0.6a(iv): Suggest why water vapour deviates significantly from ideal behaviour when the gases are cooled,...
- 19N.2.sl.TZ0.a(iv): Suggest why water vapour deviates significantly from ideal behaviour when the gases are cooled,...
-
19N.3.hl.TZ0.8:
1.40 × 10−3 g of NaOH (s) are dissolved in 250.0 cm3 of 1.00 × 10−11 mol dm−3 Pb(OH)2 (aq) solution.
Determine the change in lead ion concentration in the solution, using section 32 of the data booklet.
-
19N.3.hl.TZ0.8:
1.40 × 10−3 g of NaOH (s) are dissolved in 250.0 cm3 of 1.00 × 10−11 mol dm−3 Pb(OH)2 (aq) solution.
Determine the change in lead ion concentration in the solution, using section 32 of the data booklet.
-
19N.3.sl.TZ0.16d:
Calculate the pH of a buffer solution which contains 0.20 mol dm−3 ethanoic acid and 0.50 mol dm−3 sodium ethanoate. Use section 1 of the data booklet.
pKa (ethanoic acid) = 4.76
-
19N.3.sl.TZ0.16d:
Calculate the pH of a buffer solution which contains 0.20 mol dm−3 ethanoic acid and 0.50 mol dm−3 sodium ethanoate. Use section 1 of the data booklet.
pKa (ethanoic acid) = 4.76
-
19N.3.sl.TZ0.d:
Calculate the pH of a buffer solution which contains 0.20 mol dm−3 ethanoic acid and 0.50 mol dm−3 sodium ethanoate. Use section 1 of the data booklet.
pKa (ethanoic acid) = 4.76
-
20N.1.sl.TZ0.4:
Which volume of ethane gas, in , will produce of carbon dioxide gas when mixed with of oxygen gas, assuming the reaction goes to completion?
A.
B.
C.
D.
-
20N.1.sl.TZ0.4:
Which volume of ethane gas, in , will produce of carbon dioxide gas when mixed with of oxygen gas, assuming the reaction goes to completion?
A.
B.
C.
D.
-
20N.2.sl.TZ0.1b(ii):
Determine the limiting reactant, showing your calculations.
-
20N.2.sl.TZ0.1b(ii):
Determine the limiting reactant, showing your calculations.
-
20N.2.sl.TZ0.b(ii):
Determine the limiting reactant, showing your calculations.
-
20N.2.sl.TZ0.1b(iii):
Determine the excess amount, in , of the other reactant.
-
20N.2.sl.TZ0.1b(iii):
Determine the excess amount, in , of the other reactant.
-
20N.2.sl.TZ0.b(iii):
Determine the excess amount, in , of the other reactant.
-
20N.2.sl.TZ0.1b(iv):
Calculate the volume of chlorine, in , produced if the reaction is conducted at standard temperature and pressure (STP). Use section 2 of the data booklet.
-
20N.2.sl.TZ0.1b(iv):
Calculate the volume of chlorine, in , produced if the reaction is conducted at standard temperature and pressure (STP). Use section 2 of the data booklet.
-
20N.2.sl.TZ0.b(iv):
Calculate the volume of chlorine, in , produced if the reaction is conducted at standard temperature and pressure (STP). Use section 2 of the data booklet.
-
20N.2.hl.TZ0.1b(i):
Calculate the amount, in , of manganese(IV) oxide added.
-
20N.2.hl.TZ0.1b(i):
Calculate the amount, in , of manganese(IV) oxide added.
-
20N.2.hl.TZ0.b(i):
Calculate the amount, in , of manganese(IV) oxide added.
-
20N.2.hl.TZ0.1b(ii):
Determine the limiting reactant, showing your calculations.
-
20N.2.hl.TZ0.1b(ii):
Determine the limiting reactant, showing your calculations.
-
20N.2.hl.TZ0.b(ii):
Determine the limiting reactant, showing your calculations.
-
20N.3.sl.TZ0.9f(iii):
Suggest a wavenumber absorbed by methane gas.
-
20N.3.sl.TZ0.9f(iii):
Suggest a wavenumber absorbed by methane gas.
-
20N.3.sl.TZ0.f(iii):
Suggest a wavenumber absorbed by methane gas.
-
20N.3.sl.TZ0.10a:
Show that the mass of the isotope in the rock is .
-
20N.3.sl.TZ0.10a:
Show that the mass of the isotope in the rock is .
-
20N.3.sl.TZ0.a:
Show that the mass of the isotope in the rock is .
-
20N.3.hl.TZ0.18a(i):
Calculate the mole fraction of ethanal in the mixture.
-
20N.3.hl.TZ0.18a(i):
Calculate the mole fraction of ethanal in the mixture.
-
20N.3.hl.TZ0.a(i):
Calculate the mole fraction of ethanal in the mixture.
-
20N.3.hl.TZ0.18a(ii):
The vapour pressure of pure ethanal at is .
Calculate the vapour pressure of ethanal above the liquid mixture at .
-
20N.3.hl.TZ0.18a(ii):
The vapour pressure of pure ethanal at is .
Calculate the vapour pressure of ethanal above the liquid mixture at .
-
20N.3.hl.TZ0.a(ii):
The vapour pressure of pure ethanal at is .
Calculate the vapour pressure of ethanal above the liquid mixture at .
- 21M.1.sl.TZ1.1: Which contains the most atoms of oxygen? A. 64 g of O2 B. 1.2 × 1024 molecules of O2 C. ...
- 21M.1.sl.TZ1.1: Which contains the most atoms of oxygen? A. 64 g of O2 B. 1.2 × 1024 molecules of O2 C. ...
- 21M.1.sl.TZ1.2: What is the resulting concentration, in mol dm−3, when 1.0 cm3 of 0.500 mol dm−3 nitric...
- 21M.1.sl.TZ1.2: What is the resulting concentration, in mol dm−3, when 1.0 cm3 of 0.500 mol dm−3 nitric...
-
21M.1.sl.TZ1.3:
What volume of oxygen, in dm3 at STP, is needed when 5.8 g of butane undergoes complete combustion?
A.
B.
C.
D.
-
21M.1.sl.TZ1.3:
What volume of oxygen, in dm3 at STP, is needed when 5.8 g of butane undergoes complete combustion?
A.
B.
C.
D.
-
21M.1.sl.TZ2.1:
0.20 mol of magnesium is mixed with 0.10 mol of hydrochloric acid.
Which is correct?
-
21M.1.sl.TZ2.1:
0.20 mol of magnesium is mixed with 0.10 mol of hydrochloric acid.
Which is correct?
-
21M.2.sl.TZ1.2c:
A gaseous sample of nitrogen, contaminated only with hydrogen sulfide, was reacted with excess sodium hydroxide solution at constant temperature. The volume of the gas changed from 550 cm3 to 525 cm3.
Determine the mole percentage of hydrogen sulfide in the sample, stating one assumption you made.
-
21M.2.sl.TZ1.2c:
A gaseous sample of nitrogen, contaminated only with hydrogen sulfide, was reacted with excess sodium hydroxide solution at constant temperature. The volume of the gas changed from 550 cm3 to 525 cm3.
Determine the mole percentage of hydrogen sulfide in the sample, stating one assumption you made.
-
21M.2.sl.TZ1.c:
A gaseous sample of nitrogen, contaminated only with hydrogen sulfide, was reacted with excess sodium hydroxide solution at constant temperature. The volume of the gas changed from 550 cm3 to 525 cm3.
Determine the mole percentage of hydrogen sulfide in the sample, stating one assumption you made.
-
21M.2.sl.TZ1.4c(ii):
8.00 g of methane is completely converted to methanol. Calculate, to three significant figures, the final volume of hydrogen at STP, in dm3. Use sections 2 and 6 of the data booklet.
-
21M.2.sl.TZ1.4c(ii):
8.00 g of methane is completely converted to methanol. Calculate, to three significant figures, the final volume of hydrogen at STP, in dm3. Use sections 2 and 6 of the data booklet.
-
21M.2.sl.TZ1.c(ii):
8.00 g of methane is completely converted to methanol. Calculate, to three significant figures, the final volume of hydrogen at STP, in dm3. Use sections 2 and 6 of the data booklet.
-
21M.2.sl.TZ2.1a:
Calcium carbonate is heated to produce calcium oxide, CaO.
CaCO3 (s) → CaO (s) + CO2 (g)
Calculate the volume of carbon dioxide produced at STP when 555 g of calcium carbonate decomposes. Use sections 2 and 6 of the data booklet.
-
21M.2.sl.TZ2.1a:
Calcium carbonate is heated to produce calcium oxide, CaO.
CaCO3 (s) → CaO (s) + CO2 (g)
Calculate the volume of carbon dioxide produced at STP when 555 g of calcium carbonate decomposes. Use sections 2 and 6 of the data booklet.
-
21M.2.sl.TZ2.a:
Calcium carbonate is heated to produce calcium oxide, CaO.
CaCO3 (s) → CaO (s) + CO2 (g)
Calculate the volume of carbon dioxide produced at STP when 555 g of calcium carbonate decomposes. Use sections 2 and 6 of the data booklet.
-
21M.2.sl.TZ2.1e(i):
Determine the mass, in g, of CaCO3 (s) produced by reacting 2.41 dm3 of 2.33 × 10−2 mol dm−3 of Ca(OH)2 (aq) with 0.750 dm3 of CO2 (g) at STP.
-
21M.2.sl.TZ2.e(i):
Determine the mass, in g, of CaCO3 (s) produced by reacting 2.41 dm3 of 2.33 × 10−2 mol dm−3 of Ca(OH)2 (aq) with 0.750 dm3 of CO2 (g) at STP.
-
21M.2.sl.TZ2.1e(i):
Determine the mass, in g, of CaCO3 (s) produced by reacting 2.41 dm3 of 2.33 × 10−2 mol dm−3 of Ca(OH)2 (aq) with 0.750 dm3 of CO2 (g) at STP.
-
21M.2.sl.TZ2.1e(ii):
2.85 g of CaCO3 was collected in the experiment in e(i). Calculate the percentage yield of CaCO3.
(If you did not obtain an answer to e(i), use 4.00 g, but this is not the correct value.)
-
21M.2.sl.TZ2.e(ii):
2.85 g of CaCO3 was collected in the experiment in e(i). Calculate the percentage yield of CaCO3.
(If you did not obtain an answer to e(i), use 4.00 g, but this is not the correct value.)
-
21M.2.sl.TZ2.1e(ii):
2.85 g of CaCO3 was collected in the experiment in e(i). Calculate the percentage yield of CaCO3.
(If you did not obtain an answer to e(i), use 4.00 g, but this is not the correct value.)
-
21M.2.hl.TZ2.1a:
Calcium carbonate is heated to produce calcium oxide, CaO.
CaCO3 (s) → CaO (s) + CO2 (g)
Calculate the volume of carbon dioxide produced at STP when 555 g of calcium carbonate decomposes. Use sections 2 and 6 of the data booklet.
-
21M.2.hl.TZ2.1a:
Calcium carbonate is heated to produce calcium oxide, CaO.
CaCO3 (s) → CaO (s) + CO2 (g)
Calculate the volume of carbon dioxide produced at STP when 555 g of calcium carbonate decomposes. Use sections 2 and 6 of the data booklet.
-
21M.2.hl.TZ2.a:
Calcium carbonate is heated to produce calcium oxide, CaO.
CaCO3 (s) → CaO (s) + CO2 (g)
Calculate the volume of carbon dioxide produced at STP when 555 g of calcium carbonate decomposes. Use sections 2 and 6 of the data booklet.
-
21M.2.hl.TZ2.1c(ii):
Determine the volume, in dm3, of 0.015 mol dm−3 calcium hydroxide solution needed to neutralize 35.0 cm3 of 0.025 mol dm−3 HCl (aq).
-
21M.2.hl.TZ2.1c(ii):
Determine the volume, in dm3, of 0.015 mol dm−3 calcium hydroxide solution needed to neutralize 35.0 cm3 of 0.025 mol dm−3 HCl (aq).
-
21M.2.hl.TZ2.c(ii):
Determine the volume, in dm3, of 0.015 mol dm−3 calcium hydroxide solution needed to neutralize 35.0 cm3 of 0.025 mol dm−3 HCl (aq).
-
21M.2.hl.TZ2.1d(i):
Determine the mass, in g, of CaCO3 (s) produced by reacting 2.41 dm3 of 2.33 × 10−2 mol dm−3 of Ca(OH)2 (aq) with 0.750 dm3 of CO2 (g) at STP.
-
21M.2.hl.TZ2.1d(i):
Determine the mass, in g, of CaCO3 (s) produced by reacting 2.41 dm3 of 2.33 × 10−2 mol dm−3 of Ca(OH)2 (aq) with 0.750 dm3 of CO2 (g) at STP.
-
21M.2.hl.TZ2.d(i):
Determine the mass, in g, of CaCO3 (s) produced by reacting 2.41 dm3 of 2.33 × 10−2 mol dm−3 of Ca(OH)2 (aq) with 0.750 dm3 of CO2 (g) at STP.
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21N.2.sl.TZ0.5c:
Calculate the concentration of H3PO4 if 25.00 cm3 is completely neutralised by the addition of 28.40 cm3 of 0.5000 mol dm−3 NaOH.
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21N.2.sl.TZ0.5c:
Calculate the concentration of H3PO4 if 25.00 cm3 is completely neutralised by the addition of 28.40 cm3 of 0.5000 mol dm−3 NaOH.
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21N.2.sl.TZ0.c:
Calculate the concentration of H3PO4 if 25.00 cm3 is completely neutralised by the addition of 28.40 cm3 of 0.5000 mol dm−3 NaOH.
- 22M.1.sl.TZ2.3: Which graph represents the relationship between the amount of gas, n, and the absolute...
- 22M.1.sl.TZ2.3: Which graph represents the relationship between the amount of gas, n, and the absolute...
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22M.2.sl.TZ1.1b(iii):
Assume the reaction in (a)(i) is the only one occurring and it goes to completion, but some product has been lost from the crucible. Deduce the percentage yield of magnesium oxide in the crucible.
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22M.2.sl.TZ1.1b(iii):
Assume the reaction in (a)(i) is the only one occurring and it goes to completion, but some product has been lost from the crucible. Deduce the percentage yield of magnesium oxide in the crucible.
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22M.2.sl.TZ1.b(iii):
Assume the reaction in (a)(i) is the only one occurring and it goes to completion, but some product has been lost from the crucible. Deduce the percentage yield of magnesium oxide in the crucible.
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22M.2.sl.TZ1.2e(ii):
Determine the concentration, in mol dm–3, of the solution formed when 900.0 dm3 of NH3 (g) at 300.0 K and 100.0 kPa, is dissolved in water to form 2.00 dm3 of solution. Use sections 1 and 2 of the data booklet.
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22M.2.sl.TZ1.2e(ii):
Determine the concentration, in mol dm–3, of the solution formed when 900.0 dm3 of NH3 (g) at 300.0 K and 100.0 kPa, is dissolved in water to form 2.00 dm3 of solution. Use sections 1 and 2 of the data booklet.
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22M.2.sl.TZ1.e(ii):
Determine the concentration, in mol dm–3, of the solution formed when 900.0 dm3 of NH3 (g) at 300.0 K and 100.0 kPa, is dissolved in water to form 2.00 dm3 of solution. Use sections 1 and 2 of the data booklet.
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22M.2.hl.TZ1.1b(iii):
Assume the reaction in (a)(i) is the only one occurring and it goes to completion, but some product has been lost from the crucible. Deduce the percentage yield of magnesium oxide in the crucible.
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22M.2.hl.TZ1.1b(iii):
Assume the reaction in (a)(i) is the only one occurring and it goes to completion, but some product has been lost from the crucible. Deduce the percentage yield of magnesium oxide in the crucible.
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22M.2.hl.TZ1.b(iii):
Assume the reaction in (a)(i) is the only one occurring and it goes to completion, but some product has been lost from the crucible. Deduce the percentage yield of magnesium oxide in the crucible.
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22M.2.hl.TZ1.1c(i):
Evaluate whether this, rather than the loss of product, could explain the yield found in (b)(iii).
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22M.2.hl.TZ1.1c(i):
Evaluate whether this, rather than the loss of product, could explain the yield found in (b)(iii).
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22M.2.hl.TZ1.c(i):
Evaluate whether this, rather than the loss of product, could explain the yield found in (b)(iii).
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22M.2.hl.TZ1.4b:
Determine the concentration, in mol dm–3, of the solution formed when 900.0 dm3 of NH3 (g) at 300.0 K and 100.0 kPa, is dissolved in water to form 2.00 dm3 of solution. Use sections 1 and 2 of the data booklet.
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22M.2.hl.TZ1.4b:
Determine the concentration, in mol dm–3, of the solution formed when 900.0 dm3 of NH3 (g) at 300.0 K and 100.0 kPa, is dissolved in water to form 2.00 dm3 of solution. Use sections 1 and 2 of the data booklet.
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22M.2.hl.TZ1.b:
Determine the concentration, in mol dm–3, of the solution formed when 900.0 dm3 of NH3 (g) at 300.0 K and 100.0 kPa, is dissolved in water to form 2.00 dm3 of solution. Use sections 1 and 2 of the data booklet.
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22M.2.sl.TZ2.1b(i):
Calculate the molar concentration of the resulting solution of lithium hydroxide.
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22M.2.sl.TZ2.1b(i):
Calculate the molar concentration of the resulting solution of lithium hydroxide.
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22M.2.sl.TZ2.b(i):
Calculate the molar concentration of the resulting solution of lithium hydroxide.
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22M.2.sl.TZ2.1b(ii):
Calculate the volume of hydrogen gas produced, in cm3, if the temperature was 22.5 °C and the pressure was 103 kPa. Use sections 1 and 2 of the data booklet.
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22M.2.sl.TZ2.1b(ii):
Calculate the volume of hydrogen gas produced, in cm3, if the temperature was 22.5 °C and the pressure was 103 kPa. Use sections 1 and 2 of the data booklet.
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22M.2.sl.TZ2.b(ii):
Calculate the volume of hydrogen gas produced, in cm3, if the temperature was 22.5 °C and the pressure was 103 kPa. Use sections 1 and 2 of the data booklet.
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22N.2.sl.TZ0.5a:
Calculate the amount, in mol, of sulfur dioxide produced when 500.0 g of lignite undergoes combustion.
S (s) + O2 (g) → SO2 (g)
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22N.2.sl.TZ0.5a:
Calculate the amount, in mol, of sulfur dioxide produced when 500.0 g of lignite undergoes combustion.
S (s) + O2 (g) → SO2 (g)
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22N.2.sl.TZ0.a:
Calculate the amount, in mol, of sulfur dioxide produced when 500.0 g of lignite undergoes combustion.
S (s) + O2 (g) → SO2 (g)
- 23M.1.HL.TZ1.1: Which information does the molecular formula provide? A. The simplest ratio of atoms in a...
- 23M.1.SL.TZ1.2: Which information does the molecular formula provide? A. The simplest ratio of atoms in a...
- 23M.1.HL.TZ1.1: Which information does the molecular formula provide? A. The simplest ratio of atoms in a...
- 23M.1.SL.TZ1.2: Which information does the molecular formula provide? A. The simplest ratio of atoms in a...
- 23M.1.HL.TZ1.2: A student heated a known mass of zinc powder in an open crucible until there was no further mass...
- 23M.1.SL.TZ1.3: A student heated a known mass of zinc powder in an open crucible until there was no further mass...
- 23M.1.HL.TZ1.2: A student heated a known mass of zinc powder in an open crucible until there was no further mass...
- 23M.1.SL.TZ1.3: A student heated a known mass of zinc powder in an open crucible until there was no further mass...
- 23M.1.SL.TZ1.1: What are the units of molar mass? A. amu B. g C. mol g−1 D. g mol−1
- 23M.1.SL.TZ1.1: What are the units of molar mass? A. amu B. g C. mol g−1 D. g mol−1
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23M.1.SL.TZ2.3:
20 cm3 of gas A reacts with 20 cm3 of gas B to produce 10 cm3 of gas AxBy and 10 cm3 of excess gas A. What are the correct values for subscripts x and y in the empirical formula of the product AxBy (g)?
x y A. 2 1 B. 2 2 C. 1 1 D. 1 2 -
23M.1.HL.TZ2.2:
20 cm3 of gas A reacts with 20 cm3 of gas B to produce 10 cm3 of gas AxBy and 10 cm3 of excess gas A. What are the correct values for subscripts x and y in the empirical formula of the product AxBy (g)?
x y A. 2 1 B. 2 2 C. 1 1 D. 1 2 -
23M.1.HL.TZ2.2:
20 cm3 of gas A reacts with 20 cm3 of gas B to produce 10 cm3 of gas AxBy and 10 cm3 of excess gas A. What are the correct values for subscripts x and y in the empirical formula of the product AxBy (g)?
x y A. 2 1 B. 2 2 C. 1 1 D. 1 2 -
23M.1.SL.TZ2.3:
20 cm3 of gas A reacts with 20 cm3 of gas B to produce 10 cm3 of gas AxBy and 10 cm3 of excess gas A. What are the correct values for subscripts x and y in the empirical formula of the product AxBy (g)?
x y A. 2 1 B. 2 2 C. 1 1 D. 1 2 -
23M.2.HL.TZ1.5ai:
Draw one Lewis (electron dot) structure of the sulfate ion.
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23M.2.HL.TZ1.5ai:
Draw one Lewis (electron dot) structure of the sulfate ion.
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23M.2.HL.TZ1.i:
Draw one Lewis (electron dot) structure of the sulfate ion.
- 23M.2.HL.TZ2.1a: An unknown organic compound, X, comprising of only carbon, hydrogen and oxygen was found to...
- 23M.2.HL.TZ2.1a: An unknown organic compound, X, comprising of only carbon, hydrogen and oxygen was found to...
- 23M.2.HL.TZ2.a: An unknown organic compound, X, comprising of only carbon, hydrogen and oxygen was found to...
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23M.2.HL.TZ2.5a:
The concentration of methanoic acid was found by titration with a 0.200 mol dm−3 standard solution of sodium hydroxide, NaOH (aq), using an indicator to determine the end point.
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23M.2.HL.TZ2.5a:
The concentration of methanoic acid was found by titration with a 0.200 mol dm−3 standard solution of sodium hydroxide, NaOH (aq), using an indicator to determine the end point.
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23M.2.HL.TZ2.a:
The concentration of methanoic acid was found by titration with a 0.200 mol dm−3 standard solution of sodium hydroxide, NaOH (aq), using an indicator to determine the end point.