DP Chemistry (last assessment 2024)
Question 21N.2.hl.TZ0.6c(ii)
| Date | November 2021 | Marks available | [Maximum mark: 1] | Reference code | 21N.2.hl.TZ0.6c(ii) |
| Level | hl | Paper | 2 | Time zone | TZ0 |
| Command term | Deduce | Question number | c(ii) | Adapted from | N/A |
c(ii).
[Maximum mark: 1]
21N.2.hl.TZ0.6c(ii)
Biochemical oxygen demand (BOD) can be determined by the Winkler Method.
A 25.00 cm3 sample of water was treated according to the Winkler Method.
Step I: 2Mn2+ (aq) + O2 (g) + 4OH− (aq) → 2MnO2 (s) + 2H2O (l)
Step II: MnO2 (s) + 2I− (aq) + 4H+ (aq) → Mn2+ (aq) + I2 (aq) + 2H2O (l)
Step III: 2S2O32− (aq) + I2 (aq) → 2I− (aq) + S4O62− (aq)
The iodine produced was titrated with 37.50 cm3 of 5.000 × 10−4 mol dm−3 Na2S2O3.
(c(ii))
Deduce the mole ratio of O2 consumed in step I to S2O32− used in step III.
[1]
Markscheme
1:4 ✔
Accept “4 mol S2O32– :1 mol O2“, but not just 4:1.
