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Question 18N.2.sl.TZ0.1a.ii

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Date November 2018 Marks available [Maximum mark: 2] Reference code 18N.2.sl.TZ0.1a.ii
Level sl Paper 2 Time zone TZ0
Command term Calculate Question number a.ii Adapted from N/A
a.ii.
[Maximum mark: 2]
18N.2.sl.TZ0.1a.ii

3.26 g of iron powder are added to 80.0 cm3 of 0.200 mol dm−3 copper(II) sulfate solution. The following reaction occurs:

Fe (s) + CuSO4 (aq) → FeSO4 (aq) + Cu (s)

(a.ii)

The mass of copper obtained experimentally was 0.872 g. Calculate the percentage yield of copper.

[2]

Markscheme

ALTERNATIVE 1:
«0.0160 mol × 63.55 g mol–1 =» 1.02 «g»  ✔

« 0.872 g 1.02 g × 100 = » 85.5 «%»  ✔

 

ALTERNATIVE 2:
« 0.872 g 63.55 g mo l − − 1 = » 0.0137 «mol»  ✔

« 0.0137 mol 0.0160 mol × 100 = » 85.6 «%»  ✔

 

Accept answers in the range 85–86 %.

Award [2] for correct final answer.

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