DP Chemistry (last assessment 2024)

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Question 20N.2.hl.TZ0.b(iii)

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Date November 2020 Marks available [Maximum mark: 1] Reference code 20N.2.hl.TZ0.b(iii)
Level hl Paper 2 Time zone TZ0
Command term Determine Question number b(iii) Adapted from N/A
b(iii).
[Maximum mark: 1]
20N.2.hl.TZ0.b(iii)

Chlorine undergoes many reactions.

2.67 g of manganese(IV) oxide was added to 200.0 cm3 of 2.00 mol dm-3 HCl.

MnO2 (s)+4HCl (aq)→Cl2 (g)+2H2O (l)+MnCl2 (aq)

Determine the excess amount, in mol, of the other reactant.

[1]

Markscheme

«0.0307 mol×4=0.123 mol»

«0.400 mol–0.123 mol=»0.277 «mol» ✔

Examiners report

Surprisingly, quite a number of candidates struggled with the quantity of excess reactant despite correctly identifying limiting reactant previously.

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