DP Chemistry (last assessment 2024)

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Question 18N.2.hl.TZ0.a.i

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Date November 2018 Marks available [Maximum mark: 2] Reference code 18N.2.hl.TZ0.a.i
Level hl Paper 2 Time zone TZ0
Command term Determine Question number a.i Adapted from N/A
a.i.
[Maximum mark: 2]
18N.2.hl.TZ0.a.i

3.26 g of iron powder are added to 80.0 cm3 of 0.200 mol dm−3 copper(II) sulfate solution. The following reaction occurs:

Fe (s) + CuSO4 (aq) → FeSO4 (aq) + Cu (s)

Determine the limiting reactant showing your working.

[2]

Markscheme

nCuSO4 «= 0.0800 dm3 × 0.200 mol dm–3» = 0.0160 mol AND

nFe « 3.26 g 55.85 g mo l − 1 » = 0.0584 mol ✔

CuSO4 is the limiting reactant ✔

 

Do not award M2 if mole calculation is not shown.

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