DP Chemistry (last assessment 2024)

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Question 22N.2.hl.TZ0.5a

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Date November 2022 Marks available [Maximum mark: 2] Reference code 22N.2.hl.TZ0.5a
Level hl Paper 2 Time zone TZ0
Command term Calculate Question number a Adapted from N/A
a.
[Maximum mark: 2]
22N.2.hl.TZ0.5a

Lignite, a type of coal, contains about 0.40 % sulfur by mass.

(a)

Calculate the amount, in mol, of sulfur dioxide produced when 500.0 g of lignite undergoes combustion.

S (s) + O2 (g) → SO2 (g)

[2]

Markscheme

«0.40%×500.0 g=» 2.0 «g» ✔

«2.0 g×1 mol S32.07 g=0.062 mol of S» = 0.062 «mol of SO2» ✔

 

Award [2] for correct final answer.

Accept 0.063 «mol».

Examiners report

This question caused more problems than might have been anticipated with an average mark of 1.4/2. Many students had difficulty in calculating 0.4% of 500 g, with many getting 200 g (40% - again showing the need to read the question carefully). Even when they managed this, some used the molar mass of sulfur dioxide rather than that of sulfur.

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