DP Chemistry (last assessment 2024)
Question 21M.2.hl.TZ1.4e(iv)
Date | May 2021 | Marks available | [Maximum mark: 1] | Reference code | 21M.2.hl.TZ1.4e(iv) |
Level | hl | Paper | 2 | Time zone | TZ1 |
Command term | Predict | Question number | e(iv) | Adapted from | N/A |
e(iv).
[Maximum mark: 1]
21M.2.hl.TZ1.4e(iv)
Hydrogen peroxide can react with methane and oxygen to form methanol. This reaction can occur below 50°C if a gold nanoparticle catalyst is used.
Now consider the second stage of the reaction.
CO (g) + 2H2 (g) CH3OH (l) ΔH⦵ = –129 kJ
(e(iv))
Predict, giving a reason, how a change in temperature from 298 K to 273 K would affect the spontaneity of the reaction.
[1]
Markscheme
reaction «more» spontaneous/ΔG negative/less positive AND effect of negative entropy decreases/TΔS increases/is less negative/more positive
OR
reaction «more» spontaneous/ΔG negative/less positive AND reaction exothermic «so Kc increases » ✔
Award mark if correct calculation shown.
