Directly related questions
-
20N.2.hl.TZ0.3c:
Predict, giving a reason, whether the entropy change, , for this reaction is negative or positive.
-
20N.2.hl.TZ0.3c:
Predict, giving a reason, whether the entropy change, , for this reaction is negative or positive.
-
20N.2.hl.TZ0.c:
Predict, giving a reason, whether the entropy change, , for this reaction is negative or positive.
-
17N.2.hl.TZ0.5b:
Calculate the standard entropy change for this reaction using the following data.
-
17N.2.hl.TZ0.5b:
Calculate the standard entropy change for this reaction using the following data.
-
17N.2.hl.TZ0.b:
Calculate the standard entropy change for this reaction using the following data.
-
17N.2.hl.TZ0.5c:
The standard free energy change, ΔGθ, for the above reaction is –103 kJ mol–1 at 298 K.
Suggest why ΔGθ has a large negative value considering the sign of ΔHθ in part (a).
-
17N.2.hl.TZ0.5c:
The standard free energy change, ΔGθ, for the above reaction is –103 kJ mol–1 at 298 K.
Suggest why ΔGθ has a large negative value considering the sign of ΔHθ in part (a).
-
17N.2.hl.TZ0.c:
The standard free energy change, ΔGθ, for the above reaction is –103 kJ mol–1 at 298 K.
Suggest why ΔGθ has a large negative value considering the sign of ΔHθ in part (a).
- 21M.2.hl.TZ1.4e(iii): Justify the sign of ΔS with reference to the equation.
- 21M.2.hl.TZ1.4e(iii): Justify the sign of ΔS with reference to the equation.
- 21M.2.hl.TZ1.e(iii): Justify the sign of ΔS with reference to the equation.
- 18M.1.hl.TZ1.17: Which statement is correct? A. If ΔH < 0, reaction is always spontaneous. B. If ΔH...
- 18M.1.hl.TZ1.17: Which statement is correct? A. If ΔH < 0, reaction is always spontaneous. B. If ΔH...
-
18M.2.hl.TZ1.3c.v:
Determine, showing your working, the spontaneity of the reaction in (ii) at 25 °C.
-
18M.2.hl.TZ1.3c.v:
Determine, showing your working, the spontaneity of the reaction in (ii) at 25 °C.
-
18M.2.hl.TZ1.c.v:
Determine, showing your working, the spontaneity of the reaction in (ii) at 25 °C.
-
18M.1.hl.TZ2.17:
Which system has the most negative entropy change, ΔS, for the forward reaction?
A. N2(g) + 3H2(g) 2NH3(g)
B. CaCO3(s) → CaO(s) + CO2(g)
C. 2S2O32−(aq) + I2(aq) → S4O62−(aq) + 2I–(aq)
D. H2O(l) → H2O(g)
-
18M.1.hl.TZ2.17:
Which system has the most negative entropy change, ΔS, for the forward reaction?
A. N2(g) + 3H2(g) 2NH3(g)
B. CaCO3(s) → CaO(s) + CO2(g)
C. 2S2O32−(aq) + I2(aq) → S4O62−(aq) + 2I–(aq)
D. H2O(l) → H2O(g)
-
18M.2.hl.TZ2.5c:
The table lists standard entropy, SΘ, values.
Calculate the standard entropy change for the reaction, ΔSΘ, in J K−1.
CH4(g) + H2O(g) → 3H2(g) + CO(g)
-
18M.2.hl.TZ2.5c:
The table lists standard entropy, SΘ, values.
Calculate the standard entropy change for the reaction, ΔSΘ, in J K−1.
CH4(g) + H2O(g) → 3H2(g) + CO(g)
-
18M.2.hl.TZ2.c:
The table lists standard entropy, SΘ, values.
Calculate the standard entropy change for the reaction, ΔSΘ, in J K−1.
CH4(g) + H2O(g) → 3H2(g) + CO(g)
-
18N.1.hl.TZ0.16:
What are the signs of ΔHΘ and ΔSΘ for the reaction, which is spontaneous at low temperature and non-spontaneous at very high temperature?
ΔGΘ = ΔHΘ − TΔSΘ
SO3 (g) + CaO (s) → CaSO4 (s)
-
18N.1.hl.TZ0.16:
What are the signs of ΔHΘ and ΔSΘ for the reaction, which is spontaneous at low temperature and non-spontaneous at very high temperature?
ΔGΘ = ΔHΘ − TΔSΘ
SO3 (g) + CaO (s) → CaSO4 (s)
-
18N.2.hl.TZ0.5d:
Predict, giving your reasons, whether the forward reaction is endothermic or exothermic. Use your answers to (b) and (c).
-
18N.2.hl.TZ0.5d:
Predict, giving your reasons, whether the forward reaction is endothermic or exothermic. Use your answers to (b) and (c).
-
18N.2.hl.TZ0.d:
Predict, giving your reasons, whether the forward reaction is endothermic or exothermic. Use your answers to (b) and (c).
- 22M.1.hl.TZ2.15: What are the signs of ΔH and ΔS for a reaction that is non-spontaneous at low temperatures but...
- 22M.1.hl.TZ2.15: What are the signs of ΔH and ΔS for a reaction that is non-spontaneous at low temperatures but...
- 22M.1.hl.TZ2.17: Which term in the expression ΔG⦵ = ΔH⦵ − TΔS⦵ is an indirect measure of the entropy change of the...
- 22M.1.hl.TZ2.17: Which term in the expression ΔG⦵ = ΔH⦵ − TΔS⦵ is an indirect measure of the entropy change of the...
- 22M.2.hl.TZ1.3c(iv): Outline, with reference to the reaction equation, why this sign for the entropy change is expected.
- 22M.2.hl.TZ1.c(iv): Outline, with reference to the reaction equation, why this sign for the entropy change is expected.
- 22M.2.hl.TZ1.3c(iv): Outline, with reference to the reaction equation, why this sign for the entropy change is expected.
-
22M.2.hl.TZ2.4d(iii):
Calculate the Gibbs free energy change, ΔG⦵, in kJ mol−1, for the reaction at 298 K. Use section 1 of the data booklet.
-
22M.2.hl.TZ2.4d(iii):
Calculate the Gibbs free energy change, ΔG⦵, in kJ mol−1, for the reaction at 298 K. Use section 1 of the data booklet.
-
22M.2.hl.TZ2.d(iii):
Calculate the Gibbs free energy change, ΔG⦵, in kJ mol−1, for the reaction at 298 K. Use section 1 of the data booklet.
-
19M.1.hl.TZ1.16:
Which is correct for the reaction H2O (g) → H2O (l) ?
A. Enthalpy increases and entropy increases.
B. Enthalpy decreases and entropy increases.
C. Enthalpy increases and entropy decreases.
D. Enthalpy decreases and entropy decreases.
-
19M.1.hl.TZ1.16:
Which is correct for the reaction H2O (g) → H2O (l) ?
A. Enthalpy increases and entropy increases.
B. Enthalpy decreases and entropy increases.
C. Enthalpy increases and entropy decreases.
D. Enthalpy decreases and entropy decreases.
-
19N.1.hl.TZ0.17:
Which reaction has the greatest increase in entropy of the system?
A. HCl (g) + NH3 (g) → NH4Cl (s)
B. (NH4)2Cr2O7 (s) → Cr2O3 (s) + N2 (g) + 4H2O (g)
C. CaCO3 (s) → CaO (s) + CO2 (g)
D. I2 (g) → I2 (s)
-
19N.1.hl.TZ0.17:
Which reaction has the greatest increase in entropy of the system?
A. HCl (g) + NH3 (g) → NH4Cl (s)
B. (NH4)2Cr2O7 (s) → Cr2O3 (s) + N2 (g) + 4H2O (g)
C. CaCO3 (s) → CaO (s) + CO2 (g)
D. I2 (g) → I2 (s)
-
22N.1.hl.TZ0.16:
Which alkane has the lowest standard entropy, S⦵?
A. CH4 (g)B. C2H6 (g)
C. C3H8 (g)
D. C4H10 (g)
-
22N.1.hl.TZ0.16:
Which alkane has the lowest standard entropy, S⦵?
A. CH4 (g)B. C2H6 (g)
C. C3H8 (g)
D. C4H10 (g)
- 22N.1.hl.TZ0.17: At which temperature could ΔH, ΔS, and ΔG all be positive? A. High temperatures B. Low...
- 22N.1.hl.TZ0.17: At which temperature could ΔH, ΔS, and ΔG all be positive? A. High temperatures B. Low...
-
22N.2.hl.TZ0.1d.v:
Calculate the standard entropy change, ΔS⦵, for the dissolution of ammonium nitrate.
S⦵NH4NO3 (s) = 151.1 J mol−1 K−1
S⦵NH4NO3 (aq) = 259.8 J mol−1 K−1
-
22N.2.hl.TZ0.1d.v:
Calculate the standard entropy change, ΔS⦵, for the dissolution of ammonium nitrate.
S⦵NH4NO3 (s) = 151.1 J mol−1 K−1
S⦵NH4NO3 (aq) = 259.8 J mol−1 K−1
-
22N.2.hl.TZ0.d.v:
Calculate the standard entropy change, ΔS⦵, for the dissolution of ammonium nitrate.
S⦵NH4NO3 (s) = 151.1 J mol−1 K−1
S⦵NH4NO3 (aq) = 259.8 J mol−1 K−1
-
22N.2.hl.TZ0.1d.vi:
Calculate the standard Gibbs free energy change, ΔG⦵, in kJ mol−1, for the dissolution of ammonium nitrate at 298 K. Use sections 1 and 19 of the data booklet as well as your answer for question part (d)(v).
If you did not obtain an answer in (d)(v), use 102.3 J mol−1 K−1, although this is not the correct answer.
-
22N.2.hl.TZ0.1d.vi:
Calculate the standard Gibbs free energy change, ΔG⦵, in kJ mol−1, for the dissolution of ammonium nitrate at 298 K. Use sections 1 and 19 of the data booklet as well as your answer for question part (d)(v).
If you did not obtain an answer in (d)(v), use 102.3 J mol−1 K−1, although this is not the correct answer.
-
22N.2.hl.TZ0.d.vi:
Calculate the standard Gibbs free energy change, ΔG⦵, in kJ mol−1, for the dissolution of ammonium nitrate at 298 K. Use sections 1 and 19 of the data booklet as well as your answer for question part (d)(v).
If you did not obtain an answer in (d)(v), use 102.3 J mol−1 K−1, although this is not the correct answer.
-
17N.1.hl.TZ0.16:
What is the standard enthalpy of formation, in kJ mol–1, of IF (g)?
IF7 (g) + I2 (s) → IF5 (g) + 2IF (g) ΔH = –89 kJ
ΔH (IF7) = –941 kJ mol–1
ΔH (IF5) = –840 kJ mol–1
A. –190
B. –95
C. +6
D. +95
-
17N.1.hl.TZ0.16:
What is the standard enthalpy of formation, in kJ mol–1, of IF (g)?
IF7 (g) + I2 (s) → IF5 (g) + 2IF (g) ΔH = –89 kJ
ΔH (IF7) = –941 kJ mol–1
ΔH (IF5) = –840 kJ mol–1
A. –190
B. –95
C. +6
D. +95
-
17N.1.hl.TZ0.17:
The combustion of glucose is exothermic and occurs according to the following equation:
C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (g)
Which is correct for this reaction?
-
17N.1.hl.TZ0.17:
The combustion of glucose is exothermic and occurs according to the following equation:
C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (g)
Which is correct for this reaction?
-
18M.2.hl.TZ1.3c.iv:
Calculate the standard entropy change, ΔSΘ, in J K−1, for the reaction in (ii) using section 12 of the data booklet.
-
18M.2.hl.TZ1.3c.iv:
Calculate the standard entropy change, ΔSΘ, in J K−1, for the reaction in (ii) using section 12 of the data booklet.
-
18M.2.hl.TZ1.c.iv:
Calculate the standard entropy change, ΔSΘ, in J K−1, for the reaction in (ii) using section 12 of the data booklet.
-
18M.2.hl.TZ2.5d:
Calculate the standard free energy change, ΔGΘ, in kJ, for the reaction at 298 K using your answer to (b)(ii).
-
18M.2.hl.TZ2.5d:
Calculate the standard free energy change, ΔGΘ, in kJ, for the reaction at 298 K using your answer to (b)(ii).
-
18M.2.hl.TZ2.d:
Calculate the standard free energy change, ΔGΘ, in kJ, for the reaction at 298 K using your answer to (b)(ii).
-
18M.2.hl.TZ2.5e:
Determine the temperature, in K, above which the reaction becomes spontaneous.
-
18M.2.hl.TZ2.5e:
Determine the temperature, in K, above which the reaction becomes spontaneous.
-
18M.2.hl.TZ2.e:
Determine the temperature, in K, above which the reaction becomes spontaneous.
- 18N.2.hl.TZ0.5b: Predict, giving your reason, the sign of the standard entropy change of the forward reaction.
- 18N.2.hl.TZ0.5b: Predict, giving your reason, the sign of the standard entropy change of the forward reaction.
- 18N.2.hl.TZ0.b: Predict, giving your reason, the sign of the standard entropy change of the forward reaction.
-
19M.2.hl.TZ2.2g(i):
Determine the standard entropy change, in J K−1, for the decomposition of dinitrogen monoxide.
2N2O (g) → 2N2 (g) + O2 (g)
-
19M.2.hl.TZ2.2g(i):
Determine the standard entropy change, in J K−1, for the decomposition of dinitrogen monoxide.
2N2O (g) → 2N2 (g) + O2 (g)
-
19M.2.hl.TZ2.g(i):
Determine the standard entropy change, in J K−1, for the decomposition of dinitrogen monoxide.
2N2O (g) → 2N2 (g) + O2 (g)
-
19M.2.hl.TZ2.2g(ii):
Dinitrogen monoxide has a positive standard enthalpy of formation, ΔHfθ.
Deduce, giving reasons, whether altering the temperature would change the spontaneity of the decomposition reaction.
-
19M.2.hl.TZ2.2g(ii):
Dinitrogen monoxide has a positive standard enthalpy of formation, ΔHfθ.
Deduce, giving reasons, whether altering the temperature would change the spontaneity of the decomposition reaction.
-
19M.2.hl.TZ2.g(ii):
Dinitrogen monoxide has a positive standard enthalpy of formation, ΔHfθ.
Deduce, giving reasons, whether altering the temperature would change the spontaneity of the decomposition reaction.
-
19M.1.hl.TZ2.17:
Which change has the greatest increase in entropy?
A. CO2 (s) → CO2 (g)
B. CO2 (g) → CO2 (l)
C. CO2 (g) → CO2 (s)
D. CO2 (l) → CO2 (s)
-
19M.1.hl.TZ2.17:
Which change has the greatest increase in entropy?
A. CO2 (s) → CO2 (g)
B. CO2 (g) → CO2 (l)
C. CO2 (g) → CO2 (s)
D. CO2 (l) → CO2 (s)
-
19N.2.hl.TZ0.4a(iv):
Calculate the standard Gibbs free energy change, , in kJ mol−1, for the first dissociation of citric acid at 298 K, using section 1 of the data booklet.
-
19N.2.hl.TZ0.4a(iv):
Calculate the standard Gibbs free energy change, , in kJ mol−1, for the first dissociation of citric acid at 298 K, using section 1 of the data booklet.
-
19N.2.hl.TZ0.a(iv):
Calculate the standard Gibbs free energy change, , in kJ mol−1, for the first dissociation of citric acid at 298 K, using section 1 of the data booklet.
-
19N.2.hl.TZ0.4a(v):
Comment on the spontaneity of the reaction at 298 K.
-
19N.2.hl.TZ0.4a(v):
Comment on the spontaneity of the reaction at 298 K.
-
19N.2.hl.TZ0.a(v):
Comment on the spontaneity of the reaction at 298 K.
- 19N.2.hl.TZ0.6e(v): Deduce, giving a reason, the sign of the standard enthalpy change, ΔHθ, for the...
- 19N.2.hl.TZ0.6e(v): Deduce, giving a reason, the sign of the standard enthalpy change, ΔHθ, for the...
- 19N.2.hl.TZ0.e(v): Deduce, giving a reason, the sign of the standard enthalpy change, ΔHθ, for the...
-
19N.2.hl.TZ0.6e(vi):
Predict, giving a reason, the effect of increasing temperature on the stability of copper(I) chloride solution.
-
19N.2.hl.TZ0.6e(vi):
Predict, giving a reason, the effect of increasing temperature on the stability of copper(I) chloride solution.
-
19N.2.hl.TZ0.e(vi):
Predict, giving a reason, the effect of increasing temperature on the stability of copper(I) chloride solution.
-
20N.1.hl.TZ0.17:
Which reaction becomes more spontaneous as temperature increases?
A.
B.
C.
D.
-
20N.1.hl.TZ0.17:
Which reaction becomes more spontaneous as temperature increases?
A.
B.
C.
D.
-
20N.2.hl.TZ0.2f(ii):
Calculate the standard Gibbs free energy change, , in , for the reaction (A to B) at . Use sections 1 and 2 of the data booklet.
-
20N.2.hl.TZ0.f(ii):
Calculate the standard Gibbs free energy change, , in , for the reaction (A to B) at . Use sections 1 and 2 of the data booklet.
-
20N.2.hl.TZ0.2f(ii):
Calculate the standard Gibbs free energy change, , in , for the reaction (A to B) at . Use sections 1 and 2 of the data booklet.
-
20N.2.hl.TZ0.3d:
Calculate for the reaction in , using section 12 of the data booklet.
The standard molar entropy for oxygen gas is .
-
20N.2.hl.TZ0.3d:
Calculate for the reaction in , using section 12 of the data booklet.
The standard molar entropy for oxygen gas is .
-
20N.2.hl.TZ0.d:
Calculate for the reaction in , using section 12 of the data booklet.
The standard molar entropy for oxygen gas is .
-
20N.2.hl.TZ0.3e:
Calculate the standard Gibbs free energy change, , in , for the reaction at 5 °C, using your answers to (b) and (d). Use section 1 of the data booklet.
(If you did not obtain an answer to (b) or (d) use values of and respectively, although these are not the correct answers.)
-
20N.2.hl.TZ0.3e:
Calculate the standard Gibbs free energy change, , in , for the reaction at 5 °C, using your answers to (b) and (d). Use section 1 of the data booklet.
(If you did not obtain an answer to (b) or (d) use values of and respectively, although these are not the correct answers.)
-
20N.2.hl.TZ0.e:
Calculate the standard Gibbs free energy change, , in , for the reaction at 5 °C, using your answers to (b) and (d). Use section 1 of the data booklet.
(If you did not obtain an answer to (b) or (d) use values of and respectively, although these are not the correct answers.)
-
21M.1.hl.TZ1.16:
The table shows the variation of standard Gibbs energy with temperature for a reversible reaction.
What can be concluded about the reaction?
A. Equilibrium shifts left as temperature increases.
B. The forward reaction is more spontaneous below 300 K.
C. Entropy is higher in the products than in the reactants.
D. Kc decreases as temperature increases.
-
21M.1.hl.TZ1.16:
The table shows the variation of standard Gibbs energy with temperature for a reversible reaction.
What can be concluded about the reaction?
A. Equilibrium shifts left as temperature increases.
B. The forward reaction is more spontaneous below 300 K.
C. Entropy is higher in the products than in the reactants.
D. Kc decreases as temperature increases.
-
21M.1.hl.TZ2.17:
Which change results in the largest negative value of ΔS?
A. C2H5OH (l) + SOCl2 (l) → C2H5Cl (l) + SO2 (g) + HCl (g)
B. CaCO3 (s) → CaO (s) + CO2 (g)
C. H2O (l) → H2O (s)
D. NH3 (g) + HCl (g) → NH4Cl (s)
-
21M.1.hl.TZ2.17:
Which change results in the largest negative value of ΔS?
A. C2H5OH (l) + SOCl2 (l) → C2H5Cl (l) + SO2 (g) + HCl (g)
B. CaCO3 (s) → CaO (s) + CO2 (g)
C. H2O (l) → H2O (s)
D. NH3 (g) + HCl (g) → NH4Cl (s)
-
21M.2.hl.TZ1.4e(ii):
Calculate a value for the entropy change, ΔS⦵, in J K–1 mol–1 at 298 K. Use your answers to (e)(i) and section 1 of the data booklet.
If you did not get answers to (e)(i) use –1 kJ, but this is not the correct answer.
-
21M.2.hl.TZ1.4e(ii):
Calculate a value for the entropy change, ΔS⦵, in J K–1 mol–1 at 298 K. Use your answers to (e)(i) and section 1 of the data booklet.
If you did not get answers to (e)(i) use –1 kJ, but this is not the correct answer.
-
21M.2.hl.TZ1.e(ii):
Calculate a value for the entropy change, ΔS⦵, in J K–1 mol–1 at 298 K. Use your answers to (e)(i) and section 1 of the data booklet.
If you did not get answers to (e)(i) use –1 kJ, but this is not the correct answer.
- 21M.2.hl.TZ1.4e(iv): Predict, giving a reason, how a change in temperature from 298 K to 273 K would affect the...
- 21M.2.hl.TZ1.4e(iv): Predict, giving a reason, how a change in temperature from 298 K to 273 K would affect the...
- 21M.2.hl.TZ1.e(iv): Predict, giving a reason, how a change in temperature from 298 K to 273 K would affect the...
-
21M.2.hl.TZ2.1b(ii):
Calculate the change in entropy, ΔS, in J K−1, for the decomposition of calcium carbonate.
-
21M.2.hl.TZ2.1b(ii):
Calculate the change in entropy, ΔS, in J K−1, for the decomposition of calcium carbonate.
-
21M.2.hl.TZ2.b(ii):
Calculate the change in entropy, ΔS, in J K−1, for the decomposition of calcium carbonate.
-
21M.2.hl.TZ2.1b(iii):
Determine the temperature, in K, at which the decomposition of calcium carbonate becomes spontaneous, using b(i), b(ii) and section 1 of the data booklet.
(If you do not have answers for b(i) and b(ii), use ΔH = 190 kJ and ΔS = 180 J K−1, but these are not the correct answers.)
-
21M.2.hl.TZ2.1b(iii):
Determine the temperature, in K, at which the decomposition of calcium carbonate becomes spontaneous, using b(i), b(ii) and section 1 of the data booklet.
(If you do not have answers for b(i) and b(ii), use ΔH = 190 kJ and ΔS = 180 J K−1, but these are not the correct answers.)
-
21M.2.hl.TZ2.b(iii):
Determine the temperature, in K, at which the decomposition of calcium carbonate becomes spontaneous, using b(i), b(ii) and section 1 of the data booklet.
(If you do not have answers for b(i) and b(ii), use ΔH = 190 kJ and ΔS = 180 J K−1, but these are not the correct answers.)
- 21N.1.hl.TZ0.17: In which of the following situations is the forward reaction spontaneous? A. The equilibrium...
- 21N.1.hl.TZ0.17: In which of the following situations is the forward reaction spontaneous? A. The equilibrium...
-
21N.2.hl.TZ0.3c(ii):
Calculate the entropy change, ΔS, in J K−1 mol−1, for this reaction.
Chemistry 2e, Chpt. 21 Nuclear Chemistry, Appendix G: Standard Thermodynamic Properties for Selected Substances https://openstax.org/books/chemistry-2e/pages/g-standard-thermodynamic-properties-for- selectedsubstances# page_667adccf-f900-4d86-a13d-409c014086ea © 1999-2021, Rice University. Except where otherwise noted, textbooks on this site are licensed under a Creative Commons Attribution 4.0 International License. (CC BY 4.0) https://creativecommons.org/licenses/by/4.0/.
-
21N.2.hl.TZ0.3c(ii):
Calculate the entropy change, ΔS, in J K−1 mol−1, for this reaction.
Chemistry 2e, Chpt. 21 Nuclear Chemistry, Appendix G: Standard Thermodynamic Properties for Selected Substances https://openstax.org/books/chemistry-2e/pages/g-standard-thermodynamic-properties-for- selectedsubstances# page_667adccf-f900-4d86-a13d-409c014086ea © 1999-2021, Rice University. Except where otherwise noted, textbooks on this site are licensed under a Creative Commons Attribution 4.0 International License. (CC BY 4.0) https://creativecommons.org/licenses/by/4.0/.
-
21N.2.hl.TZ0.c(ii):
Calculate the entropy change, ΔS, in J K−1 mol−1, for this reaction.
Chemistry 2e, Chpt. 21 Nuclear Chemistry, Appendix G: Standard Thermodynamic Properties for Selected Substances https://openstax.org/books/chemistry-2e/pages/g-standard-thermodynamic-properties-for- selectedsubstances# page_667adccf-f900-4d86-a13d-409c014086ea © 1999-2021, Rice University. Except where otherwise noted, textbooks on this site are licensed under a Creative Commons Attribution 4.0 International License. (CC BY 4.0) https://creativecommons.org/licenses/by/4.0/.
-
21N.2.hl.TZ0.3c(iii):
Calculate the Gibbs free energy change (ΔG), in kJ mol−1, for this reaction at 25 °C. Use section 1 of the data booklet.
If you did not obtain an answer in c(i) or c(ii) use −87.6 kJ mol−1 and −150.5 J mol−1 K−1 respectively, but these are not the correct answers.
-
21N.2.hl.TZ0.3c(iii):
Calculate the Gibbs free energy change (ΔG), in kJ mol−1, for this reaction at 25 °C. Use section 1 of the data booklet.
If you did not obtain an answer in c(i) or c(ii) use −87.6 kJ mol−1 and −150.5 J mol−1 K−1 respectively, but these are not the correct answers.
-
21N.2.hl.TZ0.c(iii):
Calculate the Gibbs free energy change (ΔG), in kJ mol−1, for this reaction at 25 °C. Use section 1 of the data booklet.
If you did not obtain an answer in c(i) or c(ii) use −87.6 kJ mol−1 and −150.5 J mol−1 K−1 respectively, but these are not the correct answers.
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22M.1.hl.TZ1.17:
In which reaction does entropy decrease?
A. NaCl (s) → NaCl (aq)
B. Zn (s) + H2SO4 (aq) → ZnSO4 (aq) + H2 (g)
C. NH3 (g) + HCl (g) → NH4Cl (s)
D. CuCO3 (s) → CuO (s) + CO2 (g)
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22M.1.hl.TZ1.17:
In which reaction does entropy decrease?
A. NaCl (s) → NaCl (aq)
B. Zn (s) + H2SO4 (aq) → ZnSO4 (aq) + H2 (g)
C. NH3 (g) + HCl (g) → NH4Cl (s)
D. CuCO3 (s) → CuO (s) + CO2 (g)
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22M.2.hl.TZ1.3c(iii):
Calculate the entropy change for the Haber–Bosch process, in J mol–1 K–1 at 298 K. Use your answer to (b)(i) and section 1 of the data booklet.
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22M.2.hl.TZ1.c(iii):
Calculate the entropy change for the Haber–Bosch process, in J mol–1 K–1 at 298 K. Use your answer to (b)(i) and section 1 of the data booklet.
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22M.2.hl.TZ1.3c(iii):
Calculate the entropy change for the Haber–Bosch process, in J mol–1 K–1 at 298 K. Use your answer to (b)(i) and section 1 of the data booklet.
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22M.2.hl.TZ2.4d(i):
Calculate the entropy change of reaction, ΔS⦵, in J K−1 mol−1.
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22M.2.hl.TZ2.4d(i):
Calculate the entropy change of reaction, ΔS⦵, in J K−1 mol−1.
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22M.2.hl.TZ2.d(i):
Calculate the entropy change of reaction, ΔS⦵, in J K−1 mol−1.
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22M.2.hl.TZ2.4d(ii):
Predict, giving a reason, how the value of the ΔS⦵reaction would be affected if (g) were used as a reactant.
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22M.2.hl.TZ2.4d(ii):
Predict, giving a reason, how the value of the ΔS⦵reaction would be affected if (g) were used as a reactant.
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22M.2.hl.TZ2.d(ii):
Predict, giving a reason, how the value of the ΔS⦵reaction would be affected if (g) were used as a reactant.
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22N.2.hl.TZ0.1d.vii:
Calculate the value of the equilibrium constant for the dissolution of ammonium nitrate at 298 K using the answer to question part (d)(vi) and section 1 of the data booklet.
NH4NO3 (s) NH4NO3 (aq)
If you did not obtain an answer in (d)(vi), use −7.84 kJ/mol, although this is not the correct answer.
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22N.2.hl.TZ0.1d.vii:
Calculate the value of the equilibrium constant for the dissolution of ammonium nitrate at 298 K using the answer to question part (d)(vi) and section 1 of the data booklet.
NH4NO3 (s) NH4NO3 (aq)
If you did not obtain an answer in (d)(vi), use −7.84 kJ/mol, although this is not the correct answer.
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22N.2.hl.TZ0.d.vii:
Calculate the value of the equilibrium constant for the dissolution of ammonium nitrate at 298 K using the answer to question part (d)(vi) and section 1 of the data booklet.
NH4NO3 (s) NH4NO3 (aq)
If you did not obtain an answer in (d)(vi), use −7.84 kJ/mol, although this is not the correct answer.
- 22N.2.hl.TZ0.1f.iv: Predict, with a reason, the signs for the entropy change, ΔS⦵, and Gibbs free energy change, ΔG⦵,...
- 22N.2.hl.TZ0.1f.iv: Predict, with a reason, the signs for the entropy change, ΔS⦵, and Gibbs free energy change, ΔG⦵,...
- 22N.2.hl.TZ0.f.iv: Predict, with a reason, the signs for the entropy change, ΔS⦵, and Gibbs free energy change, ΔG⦵,...
- 23M.1.HL.TZ1.17: What is the correct combination of ΔH⦵ and ΔS⦵ for a reaction which is only spontaneous at high...
- 23M.1.HL.TZ1.17: What is the correct combination of ΔH⦵ and ΔS⦵ for a reaction which is only spontaneous at high...
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23M.1.SL.TZ1.14:
What is the enthalpy of combustion of propan-1-ol, in kJ mol−1, according to the following calorimetry data?
Mass of water in calorimeter 75 g Amount of propan-1-ol burned 0.015 mol Temperature rise 24 °C Specific heat capacity of water 4.2 J g−1 K−1 A.
B.
C.
D.
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23M.1.SL.TZ1.14:
What is the enthalpy of combustion of propan-1-ol, in kJ mol−1, according to the following calorimetry data?
Mass of water in calorimeter 75 g Amount of propan-1-ol burned 0.015 mol Temperature rise 24 °C Specific heat capacity of water 4.2 J g−1 K−1 A.
B.
C.
D.
- 23M.1.SL.TZ2.2: What is the mass of one molecule of C60? NA = 6.0 × 1023 A. 1.0 × 10−22 g B. 2.0 × 10−23 g C. ...
- 23M.1.HL.TZ2.1: What is the mass of one molecule of C60? NA = 6.0 × 1023 A. 1.0 × 10−22 g B. 2.0 × 10−23 g C. ...
- 23M.1.HL.TZ2.1: What is the mass of one molecule of C60? NA = 6.0 × 1023 A. 1.0 × 10−22 g B. 2.0 × 10−23 g C. ...
- 23M.1.SL.TZ2.2: What is the mass of one molecule of C60? NA = 6.0 × 1023 A. 1.0 × 10−22 g B. 2.0 × 10−23 g C. ...
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23M.2.HL.TZ2.2a:
Nitrogen (IV) oxide exists in equilibrium with dinitrogen tetroxide, N2O4 (g), which is colourless.
2NO2 (g) ⇌ N2O4 (g)
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23M.2.SL.TZ2.2a:
Nitrogen (IV) oxide exists in equilibrium with dinitrogen tetroxide, N2O4 (g), which is colourless.
2NO2 (g) ⇌ N2O4 (g)
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23M.2.HL.TZ2.2a:
Nitrogen (IV) oxide exists in equilibrium with dinitrogen tetroxide, N2O4 (g), which is colourless.
2NO2 (g) ⇌ N2O4 (g)
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23M.2.HL.TZ2.a:
Nitrogen (IV) oxide exists in equilibrium with dinitrogen tetroxide, N2O4 (g), which is colourless.
2NO2 (g) ⇌ N2O4 (g)
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23M.2.SL.TZ2.2a:
Nitrogen (IV) oxide exists in equilibrium with dinitrogen tetroxide, N2O4 (g), which is colourless.
2NO2 (g) ⇌ N2O4 (g)
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23M.2.SL.TZ2.a:
Nitrogen (IV) oxide exists in equilibrium with dinitrogen tetroxide, N2O4 (g), which is colourless.
2NO2 (g) ⇌ N2O4 (g)