DP Chemistry (last assessment 2024)

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Question 21M.2.hl.TZ1.4e(iii)

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Date May 2021 Marks available [Maximum mark: 1] Reference code 21M.2.hl.TZ1.4e(iii)
Level hl Paper 2 Time zone TZ1
Command term Justify Question number e(iii) Adapted from N/A
e(iii).
[Maximum mark: 1]
21M.2.hl.TZ1.4e(iii)

Hydrogen peroxide can react with methane and oxygen to form methanol. This reaction can occur below 50°C if a gold nanoparticle catalyst is used.

Now consider the second stage of the reaction.

CO (g) + 2H2 (g) ⇌ CH3OH (l)          ΔH⦵ = –129 kJ

(e(iii))

Justify the sign of ΔS with reference to the equation.

[1]

Markscheme

«negative as» product is liquid and reactants gases
OR
fewer moles of gas in product ✔

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