DP Chemistry (last assessment 2024)
Question 19N.2.hl.TZ0.4a(iv)
Date | November 2019 | Marks available | [Maximum mark: 1] | Reference code | 19N.2.hl.TZ0.4a(iv) |
Level | hl | Paper | 2 | Time zone | TZ0 |
Command term | Calculate | Question number | a(iv) | Adapted from | N/A |
a(iv).
[Maximum mark: 1]
19N.2.hl.TZ0.4a(iv)
A molecule of citric acid, C6H8O7, is shown.
The equation for the first dissociation of citric acid in water is
C6H8O7 (aq) + H2O (l) C6H7O7− (aq) + H3O+ (aq)
(a(iv))
Calculate the standard Gibbs free energy change, , in kJ mol−1, for the first dissociation of citric acid at 298 K, using section 1 of the data booklet.
[1]
Markscheme
« = −RT ln K = −8.31 J K–1 mol–1 × 298 K × ln(5.01 × 10–4) ÷ 1000 =» 18.8 «kJ mol–1» ✔
