DP Chemistry (last assessment 2024)

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Question 21N.2.sl.TZ0.6

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Date November 2021 Marks available [Maximum mark: 8] Reference code 21N.2.sl.TZ0.6
Level sl Paper 2 Time zone TZ0
Command term Calculate, Deduce, Determine, Outline Question number 6 Adapted from N/A
6.
[Maximum mark: 8]
21N.2.sl.TZ0.6

Biochemical oxygen demand (BOD) can be determined by the Winkler Method.

(a)

Outline what is measured by BOD.

[1]

Markscheme

«amount of» oxygen used to decompose the organic matter in water ✔

(b)

A student dissolved 0.1240 ± 0.0001 g of Na2S2O3 to make 1000.0 ± 0.4 cm3 of solution to use in the Winkler Method.

Determine the percentage uncertainty in the molar concentration.

[2]

Markscheme

«0.0001 g0.1240 g×100%=» 0.08 «%»
OR
«0.4 cm31000.0 cm3×100%=» 0.04 «%» ✔


«0.08 % + 0.04 % =» 0.12/0.1 «%» ✔


Award [2] for correct final answer.

Accept fractional uncertainties for M1, i.e., 0.0008 OR 0.0004.

A 25.00 cm3 sample of water was treated according to the Winkler Method.

Step I:   2Mn2+ (aq) + O2 (g) + 4OH− (aq) → 2MnO2 (s) + 2H2O (l)

Step II:  MnO2 (s) + 2I− (aq) + 4H+ (aq) → Mn2+ (aq) + I2 (aq) + 2H2O (l)

Step III: 2S2O32− (aq) + I2 (aq) → 2I− (aq) + S4O62− (aq)

The iodine produced was titrated with 37.50 cm3 of 5.000 × 10−4 mol dm−3 Na2S2O3.

(c(i))

Calculate the amount, in moles of Na2S2O3 used in the titration.

[1]

Markscheme

«37.50 cm31000× 5.000 × 10−4 mol dm−3 =» 1.875 × 10−5 «mol» ✔

(c(ii))

Deduce the mole ratio of O2 consumed in step I to S2O32− used in step III.

[1]

Markscheme

1:4 ✔

Accept “4 mol S2O32– :1 mol O2“, but not just 4:1.

(c(iii))

Calculate the concentration of dissolved oxygen, in mol dm−3, in the sample.

[2]

Markscheme

«1.875×10-5mol×14=» 4.688 × 10−6 «mol» ✔

«4.688×10-6 mol25.00 cm31000=» 1.875 × 10−4 «mol dm−3» ✔


Award [2] for correct final answer.

(c(iv))

The three steps of the Winkler Method are redox reactions.

Deduce the reduction half-equation for step II.

[1]

Markscheme

MnO2 (s) + 2e + 4H+ (aq) → Mn2+ (aq) + 2H2O (l) ✔