DP Chemistry (last assessment 2024)

Question 18M.2.hl.TZ2.3a.iv

Date	May 2018	Marks available	[Maximum mark: 1]	Reference code	18M.2.hl.TZ2.3a.iv
Level	hl	Paper	2	Time zone	TZ2
Command term	Calculate	Question number	a.iv	Adapted from	N/A

a.iv.

[Maximum mark: 1]

18M.2.hl.TZ2.3a.iv

The emission spectrum of an element can be used to identify it.

(a.iv)

Calculate the wavelength, in m, for the electron transition corresponding to the frequency in (a)(iii) using section 1 of the data booklet.

[1]

Markscheme

« $\lambda = \frac{C}{{\text{v}}} = \frac{{3.00 \times {{10}^8}{\text{ m}}{{\text{s}}^{ - 1}}}}{{3.28 \times {{10}^{15}}{\text{ }}{{\text{s}}^{ - 1}}}} =$ » 9.15 × 10^–8 «m»

[1 mark]

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Core

Core » Topic 2: Atomic structure » 2.2 Electron configuration

Core » Topic 2: Atomic structure

Question 18M.2.hl.TZ2.3a.iv

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