DP Chemistry (last assessment 2024)

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Question 18M.3.sl.TZ2.6

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Date May 2018 Marks available [Maximum mark: 11] Reference code 18M.3.sl.TZ2.6
Level sl Paper 3 Time zone TZ2
Command term Deduce, Determine, Explain, Identify, Outline Question number 6 Adapted from N/A
6.
[Maximum mark: 11]
18M.3.sl.TZ2.6

Lipids provide energy and are an important part of a balanced diet.

(a)

Identify the type of chemical reaction that occurs between fatty acids and glycerol to form lipids and the by-product of the reaction.

 

[2]

Markscheme

Type of reaction:

condensation

OR

esterification/triesterification

OR

nucleophilic substitution/nucleophilic displacement/SN2

 

By-product:

water/H2O

 

Do not accept just “substitution/displacement”.

[2 marks]

(b)

Arachidonic acid is a polyunsaturated omega-6 fatty acid found in peanut oil.

Determine the number of carbon–carbon double bonds present if the iodine number for the compound is 334. (Arachidonic acid Mr = 304.5)

[2]

Markscheme

ALTERNATIVE 1

« 334 253.8  =» 1.32 AND « 100 304.5  =» 0.328

« 1.32 0.328  ≈» 4

 

ALTERNATIVE 2

«334 × 304.5 100  ≈» 1017

« 1017 253.8  ≈» 4

 

Award [2] for correct final answer.

[2 marks]

(c)

Deduce the structure of the lipid formed by the reaction between lauric acid and glycerol (propane-1,2,3-triol) using section 34 of the data booklet.

[2]

Markscheme

M18/4/CHEMI/SP3/ENG/TZ2/06.c/M

glycerol backbone

ester formula AND linkage

 

Accept a skeletal structure.

Penalize missing hydrogens or incorrect bond connectivities once only in Option B.

Accept condensed formula for ester.

[2 marks]

(d)

Outline one impact food labelling has had on the consumption of foods containing different types of lipids.

[1]

Markscheme

has affected consumption of trans-fats/cis-fats/saturated fats/unsaturated fats/hydrogenated/artificially altered fats

OR

reduce/eliminate trans-fats/increase in cis-fats

OR

reduce/eliminate saturated fats

OR

increase unsaturated fats

 

Do not accept “decrease in fat” alone.

Accept “lipid” for “fats”.

[1 mark]

(e)

Determine, to the correct number of significant figures, the energy produced by the respiration of 29.9 g of C5H10O5.

ΔH(C5H10O5) = 205.9 kJ mol−1

[2]

Markscheme

« 29.9  g 150.15  g mo l 1 =» 0.199 «mol»

«0.199 mol × 205.9 kJ mol–1 =» 41.0 «kJ»

 

Ignore significant figures in M1.

Award [2] for correct final answer.

Award [1 max] for incorrect significant figures in final answer.

[2 marks]

(f)

Explain why lipids provide more energy than carbohydrates and proteins.

[2]

Markscheme

ratio of oxygen to carbon in lipids lower

OR

lipids less oxidized

OR

lipids more reduced

 

more energy per mass/g released when lipids are oxidized

 

Accept “«average» oxidation number of carbon in linoleic acid is lower” for M1.

[2 marks]