DP Chemistry (last assessment 2024)
Question 19M.3.sl.TZ1.7b
| Date | May 2019 | Marks available | [Maximum mark: 1] | Reference code | 19M.3.sl.TZ1.7b |
| Level | sl | Paper | 3 | Time zone | TZ1 |
| Command term | Formulate | Question number | b | Adapted from | N/A |
b.
[Maximum mark: 1]
19M.3.sl.TZ1.7b
Starch is a natural polymer of glucose.
(b)
Formulate the equation for the complete hydrolysis of a starch molecule, (C6H10O5)n.
[1]
Markscheme
(C6H10O5)n(s) + nH2O (l) → nC6H12O6 (aq) [✔]
Note: Accept “(n-1)H2O”.
Do not award mark if “n” not included.
Examiners report
It was very unusual to find a candidate who could give a correct equation for starch hydrolysis.
