DP Chemistry (last assessment 2024)

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Question 17N.3.sl.TZ0.b.ii

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Date November 2017 Marks available [Maximum mark: 3] Reference code 17N.3.sl.TZ0.b.ii
Level sl Paper 3 Time zone TZ0
Command term Calculate Question number b.ii Adapted from N/A
b.ii.
[Maximum mark: 3]
17N.3.sl.TZ0.b.ii

Consider the following lipid and carbohydrate.

In order to determine the number of carbon-carbon double bonds in a molecule of linoleic acid, 1.24 g of the lipid were dissolved in 10.0 cm3 of non-polar solvent.

The solution was titrated with a 0.300 mol dm–3 solution of iodine, I2.

Calculate the volume of iodine solution used to reach the end-point. 

[3]

Markscheme

« 1.24 g 280.50 g mo l − 1 =» 0.00442 «mol»

0.00884 mol of C=C

OR

ratio of linoleic acid : iodine = 1:2

«volume of I2 solution =  0.00884 mol 0.300 mol d m − 3 =» 0.0295 «dm3» / 29.5 «cm3»

Award [3] for correct final answer.

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