DP Chemistry (last assessment 2024)

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Question 18M.3.hl.TZ2.16c.i

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Date May 2018 Marks available [Maximum mark: 2] Reference code 18M.3.hl.TZ2.16c.i
Level hl Paper 3 Time zone TZ2
Command term Calculate Question number c.i Adapted from N/A
c.i.
[Maximum mark: 2]
18M.3.hl.TZ2.16c.i

Nuclear power is another source of energy.

235U atoms can be used in nuclear reactors whereas 238U cannot. A centrifuge is used to separate isotopes.

(c.i)

Calculate the relative rate of effusion of 235UF6(g) to 238UF6(g) using sections 1 and 6 of the data booklet.

[2]

Markscheme

Mr(235UF6) = 235 + (19.00 × 6)/349

OR

Mr(238UF6) = 238 + (19.00 × 6)/352

 

« rate of effusion of   235 U rate of effusion of   238 U = 352 349 = » 1.004

 

Award [2] for correct final answer.

Do not accept “1.00” OR “0.996”.

[2 marks]

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