DP Physics (last assessment 2024)
Question 19N.3.HL.TZ0.9a
Date | November 2019 | Marks available | [Maximum mark: 3] | Reference code | 19N.3.HL.TZ0.9a |
Level | HL | Paper | 3 | Time zone | TZ0 |
Command term | Explain | Question number | a | Adapted from | N/A |
a.
[Maximum mark: 3]
19N.3.HL.TZ0.9a
A Pitot tube shown in the diagram is used to determine the speed of air flowing steadily in a horizontal wind tunnel. The narrow tube between points A and B is filled with a liquid. At point B the speed of the air is zero.
(a)
Explain why the levels of the liquid are at different heights.
[3]
Markscheme
air speed at A greater than at B/speed at B is zero
OR
total/stagnation pressure «PB» – static pressure «PA» = dynamic pressure ✔
so PA is less than at PB (or vice versa) «by Bernoulli effect» ✔
height of the liquid column is related to «dynamic» pressure difference «hence lower height in arm B» ✔
