DP Physics (last assessment 2024)
Question 17N.2.SL.TZ0.4b.i
| Date | November 2017 | Marks available | [Maximum mark: 4] | Reference code | 17N.2.SL.TZ0.4b.i |
| Level | SL | Paper | 2 | Time zone | TZ0 |
| Command term | Determine | Question number | b.i | Adapted from | N/A |
b.i.
[Maximum mark: 4]
17N.2.SL.TZ0.4b.i
Each side of the ice cube is 0.75 m in length. The initial temperature of the ice cube is –20 °C.
(b.i)
Determine the energy required to melt all of the ice from –20 °C to water at a temperature of 0 °C.
Specific latent heat of fusion of ice = 330 kJ kg–1
Specific heat capacity of ice = 2.1 kJ kg–1 k–1
Density of ice = 920 kg m–3
[4]
Markscheme
mass = «volume x density» (0.75)3 x 920 «= 388 kg»
energy required to raise temperature = 388 x 2100 x 20 «= 1.63 x 107 J»
energy required to melt = 388 x 330 x 103 «= 1.28 x 108 J»
1.4 x 108 «J» OR 1.4 x 105 «kJ»
Accept any consistent units
Award [3 max] for answer which uses density as 1000 kg–3 (1.5× 108 «J»)
