Question 18M.2.HL.TZ2.6
Date | May 2018 | Marks available | [Maximum mark: 11] | Reference code | 18M.2.HL.TZ2.6 |
Level | HL | Paper | 2 | Time zone | TZ2 |
Command term | Calculate, Draw, Estimate, Show that, State | Question number | 6 | Adapted from | N/A |
A planet has radius R. At a distance h above the surface of the planet the gravitational field strength is g and the gravitational potential is V.
State what is meant by gravitational field strength.
[1]
the «gravitational» force per unit mass exerted on a point/small/test mass
[1 mark]

Show that V = –g(R + h).
[2]
at height h potential is V = –
field is g =
«dividing gives answer»
Do not allow an answer that starts with g = – and then cancels the deltas and substitutes R + h
[2 marks]

Draw a graph, on the axes, to show the variation of the gravitational potential V of the planet with height h above the surface of the planet.
[2]
correct shape and sign
non-zero negative vertical intercept
[2 marks]
A planet has a radius of 3.1 × 106 m. At a point P a distance 2.4 × 107 m above the surface of the planet the gravitational field strength is 2.2 N kg–1. Calculate the gravitational potential at point P, include an appropriate unit for your answer.
[1]
V = «–2.2 × (3.1 × 106 + 2.4 × 107) =» «–» 6.0 × 107 J kg–1
Unit is essential
Allow eg MJ kg–1 if power of 10 is correct
Allow other correct SI units eg m2s–2, N m kg–1
[1 mark]

The diagram shows the path of an asteroid as it moves past the planet.
When the asteroid was far away from the planet it had negligible speed. Estimate the speed of the asteroid at point P as defined in (b).
[3]
total energy at P = 0 / KE gained = GPE lost
«mv2 + mV = 0 ⇒» v =
v = « =» 1.1 × 104 «ms–1»
Award [3] for a bald correct answer
Ignore negative sign errors in the workings
Allow ECF from 6(b)
[3 marks]

The mass of the asteroid is 6.2 × 1012 kg. Calculate the gravitational force experienced by the planet when the asteroid is at point P.
[2]
ALTERNATIVE 1
force on asteroid is «6.2 × 1012 × 2.2 =» 1.4 × 1013 «N»
«by Newton’s third law» this is also the force on the planet
ALTERNATIVE 2
mass of planet = 2.4 x 1025 «kg» «from V = –»
force on planet «» = 1.4 × 1013 «N»
MP2 must be explicit
[2 marks]
