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6.2 – Newton’s law of gravitation
Description
Nature of science:
Laws: Newton’s law of gravitation and the laws of mechanics are the foundation for deterministic classical physics. These can be used to make predictions but do not explain why the observed phenomena exist. (2.4)
Understandings:
- Newton’s law of gravitation
- Gravitational field strength
Applications and skills:
- Describing the relationship between gravitational force and centripetal force
- Applying Newton’s law of gravitation to the motion of an object in circular orbit around a point mass
- Solving problems involving gravitational force, gravitational field strength, orbital speed and orbital period
- Determining the resultant gravitational field strength due to two bodies
Guidance:
- Newton’s law of gravitation should be extended to spherical masses of uniform density by assuming that their mass is concentrated at their centre
- Gravitational field strength at a point is the force per unit mass experienced by a small point mass at that point
- Calculations of the resultant gravitational field strength due to two bodies will be restricted to points along the straight line joining the bodies
Data booklet reference:
Theory of knowledge:
- The laws of mechanics along with the law of gravitation create the deterministic nature of classical physics. Are classical physics and modern physics compatible? Do other areas of knowledge also have a similar division between classical and modern in their historical development?
Utilization:
- The law of gravitation is essential in describing the motion of satellites, planets, moons and entire galaxies
- Comparison to Coulomb’s law (see Physics sub-topic 5.1)
Aims:
- Aim 4: the theory of gravitation when combined and synthesized with the rest of the laws of mechanics allows detailed predictions about the future position and motion of planets
Directly related questions
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17N.2.SL.TZ0.5a:
Determine the orbital period for the satellite.
Mass of Earth = 6.0 x 1024 kg
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17N.2.SL.TZ0.5a:
Determine the orbital period for the satellite.
Mass of Earth = 6.0 x 1024 kg
-
17N.2.SL.TZ0.a:
Determine the orbital period for the satellite.
Mass of Earth = 6.0 x 1024 kg
- 21M.2.HL.TZ1.2a: Explain why a centripetal force is needed for the planet to be in a circular orbit.
- 21M.2.HL.TZ1.2a: Explain why a centripetal force is needed for the planet to be in a circular orbit.
- 21M.2.HL.TZ1.a: Explain why a centripetal force is needed for the planet to be in a circular orbit.
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21M.1.SL.TZ1.23:
Which is the definition of gravitational field strength at a point?
A. The sum of the gravitational fields created by all masses around the point
B. The gravitational force per unit mass experienced by a small point mass at that point
C. , where is the mass of a planet and is the distance from the planet to the point
D. The resultant force of gravitational attraction on a mass at that point
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21M.1.SL.TZ1.23:
Which is the definition of gravitational field strength at a point?
A. The sum of the gravitational fields created by all masses around the point
B. The gravitational force per unit mass experienced by a small point mass at that point
C. , where is the mass of a planet and is the distance from the planet to the point
D. The resultant force of gravitational attraction on a mass at that point
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21N.2.SL.TZ0.6b.i:
The orbital radius of Titan around Saturn is and the period of revolution is .
Show that where is the mass of Saturn.
-
21N.2.SL.TZ0.6b.i:
The orbital radius of Titan around Saturn is and the period of revolution is .
Show that where is the mass of Saturn.
-
21N.2.SL.TZ0.b.i:
The orbital radius of Titan around Saturn is and the period of revolution is .
Show that where is the mass of Saturn.
-
21N.2.SL.TZ0.6b.ii:
The orbital radius of Titan around Saturn is 1.2 × 109 m and the orbital period is 15.9 days. Estimate the mass of Saturn.
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21N.2.SL.TZ0.6b.ii:
The orbital radius of Titan around Saturn is 1.2 × 109 m and the orbital period is 15.9 days. Estimate the mass of Saturn.
-
21N.2.SL.TZ0.b.ii:
The orbital radius of Titan around Saturn is 1.2 × 109 m and the orbital period is 15.9 days. Estimate the mass of Saturn.
-
21N.2.HL.TZ0.6c.i:
The orbital radius of Titan around Saturn is and the period of revolution is .
Show that where is the mass of Saturn.
-
21N.2.HL.TZ0.6c.i:
The orbital radius of Titan around Saturn is and the period of revolution is .
Show that where is the mass of Saturn.
-
21N.2.HL.TZ0.c.i:
The orbital radius of Titan around Saturn is and the period of revolution is .
Show that where is the mass of Saturn.
-
21N.2.HL.TZ0.6c.ii:
The orbital radius of Titan around Saturn is 1.2 × 109 m and the orbital period is 15.9 days. Estimate the mass of Saturn.
-
21N.2.HL.TZ0.6c.ii:
The orbital radius of Titan around Saturn is 1.2 × 109 m and the orbital period is 15.9 days. Estimate the mass of Saturn.
-
21N.2.HL.TZ0.c.ii:
The orbital radius of Titan around Saturn is 1.2 × 109 m and the orbital period is 15.9 days. Estimate the mass of Saturn.
- 18N.2.SL.TZ0.1d.ii: Newton’s law of gravitation applies to point masses. Suggest why the law can be applied to a...
- 18N.2.SL.TZ0.1d.ii: Newton’s law of gravitation applies to point masses. Suggest why the law can be applied to a...
- 18N.2.SL.TZ0.d.ii: Newton’s law of gravitation applies to point masses. Suggest why the law can be applied to a...
- 18N.2.SL.TZ0.1d.i: Outline what is meant by the gravitational field strength at a point.
- 18N.2.SL.TZ0.1d.i: Outline what is meant by the gravitational field strength at a point.
- 18N.2.SL.TZ0.d.i: Outline what is meant by the gravitational field strength at a point.
- 18N.2.HL.TZ0.8a.ii: Newton’s law of gravitation applies to point masses. Suggest why the law can be applied to a...
- 18N.2.HL.TZ0.8a.ii: Newton’s law of gravitation applies to point masses. Suggest why the law can be applied to a...
- 18N.2.HL.TZ0.a.ii: Newton’s law of gravitation applies to point masses. Suggest why the law can be applied to a...
- 19M.2.SL.TZ1.6c.i: Outline why a force acts on the Moon.
- 19M.2.SL.TZ1.6c.i: Outline why a force acts on the Moon.
- 19M.2.SL.TZ1.c.i: Outline why a force acts on the Moon.
- 19M.1.SL.TZ2.23: Which graph shows the relationship between gravitational force F between two point masses and...
- 19M.1.SL.TZ2.23: Which graph shows the relationship between gravitational force F between two point masses and...
- 19N.1.SL.TZ0.23: A satellite travels around the Earth in a circular orbit. What is true about the forces acting in...
- 19N.1.SL.TZ0.23: A satellite travels around the Earth in a circular orbit. What is true about the forces acting in...
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22N.1.SL.TZ0.22:
The centre of the Earth and the Moon are a distance apart. There is a point X between them where their gravitational fields cancel out. The distance from the centre of the Earth to X is . The mass of the Earth is and the mass of the Moon is .
What is correct at X?
A.B.
C.
D.
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22N.1.SL.TZ0.22:
The centre of the Earth and the Moon are a distance apart. There is a point X between them where their gravitational fields cancel out. The distance from the centre of the Earth to X is . The mass of the Earth is and the mass of the Moon is .
What is correct at X?
A.B.
C.
D.
- 18M.1.SL.TZ1.23: Newton’s law of gravitation A. is equivalent to Newton’s second law of motion. B. ...
- 18M.1.SL.TZ1.23: Newton’s law of gravitation A. is equivalent to Newton’s second law of motion. B. ...
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18M.2.HL.TZ2.6a.i:
State what is meant by gravitational field strength.
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18M.2.HL.TZ2.6a.i:
State what is meant by gravitational field strength.
-
18M.2.HL.TZ2.a.i:
State what is meant by gravitational field strength.
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18M.2.HL.TZ2.6d:
The mass of the asteroid is 6.2 × 1012 kg. Calculate the gravitational force experienced by the planet when the asteroid is at point P.
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18M.2.HL.TZ2.6d:
The mass of the asteroid is 6.2 × 1012 kg. Calculate the gravitational force experienced by the planet when the asteroid is at point P.
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18M.2.HL.TZ2.d:
The mass of the asteroid is 6.2 × 1012 kg. Calculate the gravitational force experienced by the planet when the asteroid is at point P.
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18N.1.SL.TZ0.23:
Two isolated point particles of mass 4M and 9M are separated by a distance 1 m. A point particle of mass M is placed a distance from the particle of mass 9M. The net gravitational force on M is zero.
What is ?
A. m
B. m
C. m
D. m
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18N.1.SL.TZ0.23:
Two isolated point particles of mass 4M and 9M are separated by a distance 1 m. A point particle of mass M is placed a distance from the particle of mass 9M. The net gravitational force on M is zero.
What is ?
A. m
B. m
C. m
D. m
- 18N.2.HL.TZ0.8a.i: Outline what is meant by gravitational field strength at a point.
- 18N.2.HL.TZ0.8a.i: Outline what is meant by gravitational field strength at a point.
- 18N.2.HL.TZ0.a.i: Outline what is meant by gravitational field strength at a point.
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18N.2.HL.TZ0.8b.i:
Mars has a mass of 6.4 × 1023 kg. Show that, for Mars, k is about 9 × 10–13 s2 m–3.
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18N.2.HL.TZ0.8b.i:
Mars has a mass of 6.4 × 1023 kg. Show that, for Mars, k is about 9 × 10–13 s2 m–3.
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18N.2.HL.TZ0.b.i:
Mars has a mass of 6.4 × 1023 kg. Show that, for Mars, k is about 9 × 10–13 s2 m–3.
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18N.2.HL.TZ0.8b.ii:
The time taken for Mars to revolve on its axis is 8.9 × 104 s. Calculate, in m s–1, the orbital speed of the satellite.
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18N.2.HL.TZ0.8b.ii:
The time taken for Mars to revolve on its axis is 8.9 × 104 s. Calculate, in m s–1, the orbital speed of the satellite.
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18N.2.HL.TZ0.b.ii:
The time taken for Mars to revolve on its axis is 8.9 × 104 s. Calculate, in m s–1, the orbital speed of the satellite.
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19M.1.SL.TZ1.25:
Satellite X orbits a planet with orbital radius R. Satellite Y orbits the same planet with orbital radius 2R. Satellites X and Y have the same mass.
What is the ratio ?
A.
B.
C. 2
D. 4
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19M.1.SL.TZ1.25:
Satellite X orbits a planet with orbital radius R. Satellite Y orbits the same planet with orbital radius 2R. Satellites X and Y have the same mass.
What is the ratio ?
A.
B.
C. 2
D. 4
- 19M.2.HL.TZ1.5a.i: Outline the origin of the force that acts on Phobos.
- 19M.2.HL.TZ1.5a.i: Outline the origin of the force that acts on Phobos.
- 19M.2.HL.TZ1.a.i: Outline the origin of the force that acts on Phobos.
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20N.1.SL.TZ0.23:
Planet X has a gravitational field strength of at its surface. Planet Y has the same density as X but three times the radius of X. What is the gravitational field strength at the surface of Y?
A.
B.
C.
D.
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20N.1.SL.TZ0.23:
Planet X has a gravitational field strength of at its surface. Planet Y has the same density as X but three times the radius of X. What is the gravitational field strength at the surface of Y?
A.
B.
C.
D.
- 20N.1.HL.TZ0.30: Two satellites W and X have the same mass. They have circular orbits around the same planet. W is...
- 20N.1.HL.TZ0.30: Two satellites W and X have the same mass. They have circular orbits around the same planet. W is...
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21M.2.HL.TZ2.10a:
Calculate, for the surface of , the gravitational field strength gIo due to the mass of . State an appropriate unit for your answer.
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21M.2.HL.TZ2.10a:
Calculate, for the surface of , the gravitational field strength gIo due to the mass of . State an appropriate unit for your answer.
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21M.2.HL.TZ2.a:
Calculate, for the surface of , the gravitational field strength gIo due to the mass of . State an appropriate unit for your answer.
- 21M.2.SL.TZ1.2a.i: Explain why a centripetal force is needed for the planet to be in a circular orbit.
- 21M.2.SL.TZ1.2a.i: Explain why a centripetal force is needed for the planet to be in a circular orbit.
- 21M.2.SL.TZ1.a.i: Explain why a centripetal force is needed for the planet to be in a circular orbit.
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21M.2.SL.TZ1.2b:
Determine the gravitational field of the planet.
The following data are given:
Mass of planet kg
Radius of the planet m. -
21M.2.SL.TZ1.2b:
Determine the gravitational field of the planet.
The following data are given:
Mass of planet kg
Radius of the planet m. -
21M.2.SL.TZ1.b:
Determine the gravitational field of the planet.
The following data are given:
Mass of planet kg
Radius of the planet m. -
21N.1.SL.TZ0.23:
The gravitational field strength at the surface of a planet of radius R is . A satellite is moving in a circular orbit a distance R above the surface of the planet. What is the magnitude of the acceleration of the satellite?
A.B.
C.
D.
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21N.1.SL.TZ0.23:
The gravitational field strength at the surface of a planet of radius R is . A satellite is moving in a circular orbit a distance R above the surface of the planet. What is the magnitude of the acceleration of the satellite?
A.B.
C.
D.
- 22M.1.SL.TZ2.24: Three statements about Newton’s law of gravitation are: I. It can be used to predict the...
- 22M.1.SL.TZ2.24: Three statements about Newton’s law of gravitation are: I. It can be used to predict the...
- 22M.1.HL.TZ2.21: An astronaut is orbiting Earth in a spaceship. Why does the astronaut experience...
- 22M.1.HL.TZ2.21: An astronaut is orbiting Earth in a spaceship. Why does the astronaut experience...
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22M.1.HL.TZ1.24:
P and Q are two moons of equal densities orbiting a planet. The orbital radius of P is twice the orbital radius of Q. The volume of P is half that of Q. The force exerted by the planet on P is F. What is the force exerted by the planet on Q?
A. F
B. 2F
C. 4F
D. 8F
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22M.1.HL.TZ1.24:
P and Q are two moons of equal densities orbiting a planet. The orbital radius of P is twice the orbital radius of Q. The volume of P is half that of Q. The force exerted by the planet on P is F. What is the force exerted by the planet on Q?
A. F
B. 2F
C. 4F
D. 8F